A rectangular loop of wire that can rotate about an axis through its center is placed between the poles of a magnet in a magneti
c field with a strength of 0.40 T. The length of the loop L is 0.16 m and its width w is 0.040 m. What is the magnetic flux through the loop when the plane of the loop is perpendicular to the magnetic field?
1 answer:
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Note: I assume the mirror is concave, so that its focal length is positive (it is not specified in the text)
1a) We can use the mirror equation to find the distance of the image from the mirror:
where
is the focal length
is the distance of the object from the mirror
is the distance of the image from the mirror.
Rearranging the equation, we find
so, the distance of the image from the mirror is
.
1b) The image height is given by the magnification equation:
where
is the heigth of the image and 
is the height of the object. By rearranging the equation and using p and q, we find
and the negative sign means the image is inverted.
2) As before, we can find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
3) As before, we find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
And now we can use the magnification equation to find the image height:
Rearranging it, we find
and the negative sign means the image is inverted.
1a) We can use the mirror equation to find the distance of the image from the mirror:
where
Rearranging the equation, we find
so, the distance of the image from the mirror is
1b) The image height is given by the magnification equation:
where
and the negative sign means the image is inverted.
2) As before, we can find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
3) As before, we find the distance of the image from the mirror by using the mirror equation:
Rearranging it, we find
so, the distance of the image from the mirror is
And now we can use the magnification equation to find the image height:
Rearranging it, we find
and the negative sign means the image is inverted.