A(n) 2602 kg van runs into the back of a(n)

A 9.76-m ladder with a mass of 22.6 kg lies flat on the ground. A painter grabs the top end of the ladder and pulls straight upw

galben [10]

Answer:

Part a)

$\tau_{net} = 1397.1 Nm$

Part b)

$I = 702.06 kg m^2$

Explanation:

Part a)

Torque on the rod is due to two forces

(i) Due to weight of the rod at mid point

(ii) Due to external force applied at the end

Now we have

$\tau_{net} = FL - mg\frac{L}{2}$

$\tau_{net} = 254(9.76) - (22.6)(9.81)(\frac{9.76}{2})$

$\tau_{net} = 1397.1 Nm$

Part b)

As per Newton's law we know that

$\tau = I\alpha$

now we have

$1397.1 Nm = I(1.99 rad/s^2)$

$I = 702.06 kg m^2$

6 0

3 years ago

If the gravitational field strength at the top of Mount Everest is 9.772 N/kg, approximately how tall (in feet) is

Delicious77 [7]

Answer:

The height of the Everest mountain is, x = 8514.087 m

Explanation:

Given data,

The gravitational field strength at the top of mount Everest, gₓ = 9.772 m/s²

The formula for gravitational field strength is,

Where, x is the height from the surface of the Earth

Therefore,

(R+x)² = GM/gₓ

x = √(GM/gₓ) - R

Substituting the values,

x = √(6.67408 x 10⁻¹¹ X 5.972 x 10²⁴ / 9.772) - 6.378 x 10⁶

x = 8514.087 m

Therefore, the height of the Everest mountain is, x = 8514.087 m

6 0

3 years ago

0.10-kilogram model rocket’s engine is designed to deliver an impulse of 6.0 newton-seconds. If the rocket engine burns for 0.75

UkoKoshka [18]

Answer:

8.0 N

Explanation:

Force: This can be defined as the mass of a body and its acceleration. The S.I unit of Force is Newton (N).

Mathematically, Fore is expressed as

F = ma ........................... equation 1

Where F = force, m = mass, a = acceleration.

and

I = mΔv

Δv = I/m ............................ Equation 2

Where I = impulse, m = mass, Δv = change in velocity

Given: I = 6.0 Newton-seconds, m = 0.1 kilogram.

Substituting into equation 2

Δv = 6.0/0.1

Δv = 60 m/s.

But

a = Δv/t

where t = time = 0.75 seconds.

a = 60/0.75

a = 80 m/s²

Substitute the values of a and m into equation 1.

F = 0.1(80)

F = 8.0 N.

Thus the average force produced = 8.0 N

6 0

3 years ago

When two hydrogen atoms bond, the positive nucleus of one atom attracts the

mafiozo [28]

<span>When two hydrogen atoms bond, the positive nucleus of one atom attracts the electrons of both the atoms since the electrons are shared between the two atoms now.</span>

6 0

3 years ago

After driving a portion of the route, the taptap is fully loaded with a total of 25 people including the driver, with an average

alexira [117]

Answer:

Incomplete Question

Explanation:

String constant is not stated

I'll solve this in a general way.

At the end of my explanation, I'll assume any value for string constant.

The total weight on the taptap : Weight of people + Weight of goats + Weight of chickens + weight of banana

= (25 * 66) + (3 * 15) + (5 * 3) + 25 = 1735 kg

The gravitational force exerted on the taptap

Fig = m*g

where m = the total mass 1735kg

and g = 9.8m/s²

Hooke's law of Elasticity states that

Fs = Kx

Where Fs = spring force

k = spring constant

x = spring stretch or compression

Since Fs = Fg

So, Kx = mg

Make x the subject of the formula

x = mg/k --------------- This is the general way of solving for spring compressor in cases like this

I'll replace m and g with their values, respectively.

Because, the spring constant (k) is omitted in the question, I'll assume it to be 30000

x = 1735 * 9.8/30000

x = 17003/30000

x = 0.566767 metres

x = 0.57 metres ------------- Approximated

In conclusion, the spring compression is 0.57 metres if the spring constant is 30000

6 0

3 years ago