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3 years ago

What is serve in volleyball?

Physics

2 answers:

galina1969 [7]3 years ago

4 0

Answer:

In volleyball, the serve is the act of putting the ball in play by a player sounds simple, but actually it describes one of the most important plays in the game of volleyball. ... The ball is held in the left hand to the front and right side of the body so that it will be directly in line with the right hand.

madreJ [45]3 years ago

3 0

Underhand serve is a type of volleyball serve in which a player holds the ball with one hand and swings the other hand in an arc motion, striking under the ball with a fist to put it into play. An underhand serve is the most common serve for beginners.

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Explanation:

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nirvana33 [79]

Answer:

a) $F = 882.63\,N$ , b) $\dot W= 4413.15\,W$ , c) $\eta = 15.216\,\%$ .

Explanation:

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$\Sigma F_{x} = F - \mu_{r}\cdot N = 0$

$\Sigma F_{y} = N - m\cdot g = 0$

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b) The power require to move the car at a speed of 5 meters per second is:

$\dot W = F\cdot v$

$\dot W = (882.63\,N)\cdot (5\,\frac{m}{s} )$

$\dot W= 4413.15\,W$

c) The efficiency of the car is:

$\eta = \frac{(882.63\,N)\cdot (15\,mi)\cdot (\frac{1609\,m}{1\,mi} )}{(1.4\times 10^{8}\,J)} \times 100\,\%$

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The first thing you should know in this case is the following definition:
PV = nRT
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PV = k
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P1V1 = k
P2V2 = k
We can then equalize both equations:
P1V1 = P2V2
Substituting the values:
(1.25) * (101) = (2.25) * (P2)
Clearing P2:
P2 = ((1.25) * (101)) /(2.25)=56.11Kpa
answer:
the new pressure inside the jar is 56.11Kpa

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