Answer:
Step-by-step explanation:
1) 9,06
2) 85,3018
3) 0,052121
4) 0,917123
5) 17,9807
6) 2267,96
7) 169,07
8) 0,211338
I'm guessing you mean magazines as in bullets. Well, if he paid $412 dollars for two, and each were sold as a multiple of 43. Then each bullet was $4.79.
You find this by dividing 412 by 2 which gives you $206.
Now divide that by 43. Which is $4.79 (.ea) bullet.
Ms. Cassidy instructed Miguel to change one sign of the graph of y < 2x – 4 so that point (2, 3) can be included in the solution set.
To check which of the given options might Miguel write we check the inequality that holds true for the point (2,3).Substituting x=2 ,y=3 we have:
1) y < 2x – 1
3<2(2)-1
3<3 Not True.
2)y ≤ 2x – 4
3≤ 2(2) -4
3≤ 0 .Not true.
3) y > 2x – 4
3> 2(2)-4
3> 0 True.
4) y < 2x + 4
3<2(2)+4
3<8 True
5) .y < 3.5x – 4
3< 3.5(2)-4
3<3 Not true
6) y < 4x – 4
3<4(2)-4
3<4 True.
Options 3 ,4 ,6 holds true for the point (2,3)
Answer:
Step-by-step explanation:
Nice summary problem.
<AEC
- AEC = 360 - 243.5 = 116.5
- The number of degrees in 1 rotation of a circle = 360o. You have accounted for 243.5 degrees. What is left over is the answer.
<EAD and <ECD
Both of these are tangents to a circle. Tangents meet radii at 90 degree angles.
<EAD = <ECD = 90 degrees
<ABC
<ABC is 1/2 the central angle. The Central angle is <AEC
- < AEC = 116.5
- <ABC = 1/2 * 116.5
- <ABC = 58.25
<ADC
There are 2 ways of doing this. You should know both of them.
<em><u>One</u></em>
All quadrilaterals = 360 degrees. You know three of the angles. You should be able to find ADC
- <ADC + 90 + 90 + 116.5 = 360 Add the four angles together.
- <ADC + 296.5 = 360 Combine terms on the left
- <ADC = 360 - 296.5 Subtract 238.25 from both sides
- <ADC = 63.5 Answer
<em><u>Method Two</u></em>
<ADC = 1/2 (major Arc - Minor Arc) This formula is fundamental to circle / tangent properties. The Major arc is the larger of the two parts of the circumference of a circle. The Minor arc is the smaller.
- <ADC = 1/2(243.5 - 116.5)
- <ADC = 1/2(127)
- <ADC = 63.5
When converted to a household measurement, 9 kilograms is approximately equal to a
