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mojhsa [17]
2 years ago
10

If the shaded sector is 75m what would the area be of the circle? A. 30 B. 36 C.144 D. 108

Mathematics
1 answer:
fredd [130]2 years ago
8 0
The correct answer is letter B
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BRAINLIEST can someone please help!!!!!
Zielflug [23.3K]

I don't know about the first one but for the second one:

{2}^{3x + 2}  -  {2}^{3x}  = 48 \\ \Leftrightarrow {2}^{3x}  {2}^{2}  -  {2}^{3x}  = 48 \\ \Leftrightarrow  {2}^{3x} ( 4  - 1) = 48 \\ \Leftrightarrow 3 \times  {2}^{3x}  = 48 \\ \Leftrightarrow  {2}^{3x}  = 16 \\ \Leftrightarrow  {2}^{3x}  =  {2}^{4}  \\ \Leftrightarrow 3x = 4\Leftrightarrow x =  \frac{4}{3}

4 0
3 years ago
Consider the following function. f(x) = 16 − x2/3 Find f(−64) and f(64). f(−64) = f(64) = Find all values c in (−64, 64) such th
VARVARA [1.3K]

Answer:

This does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64).

Step-by-step explanation:

The given function is

f(x)=16-\frac{x^2}{3}

To find f(-64), we substitute x=-64 into the function.

f(-64)=16-\frac{(-64)^2}{3}

f(-64)=16-\frac{4096}{3}

f(-64)=-\frac{4048}{3}

To find f(64), we substitute x=64 into the function.

f(64)=16-\frac{(64)^2}{3}

f(64)=16-\frac{4096}{3}

f(64)=-\frac{4048}{3}

To find f'(c), we must first find f'(x).

f'(x)=-\frac{2x}{3}

This implies that;

f'(c)=-\frac{2c}{3}

f'(c)=0

\Rightarrow -\frac{2c}{3}=0

\Rightarrow -\frac{2c}{3}\times -\frac{3}{2}=0\times -\frac{3}{2}

c=0

For this function to satisfy the Rolle's Theorem;

It must be continuous on [-64,64].

It must be differentiable  on (-64,64).

and

f(-64)=f(64).

All the hypotheses are met, hence this does not contradict Rolle's Theorem, since f '(0) = 0, and 0 is in the interval (−64, 64) is the correct choice.

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Why can you multiply the numerator and the denominator of a fraction by the same number to find a equivalent fraction?
OLga [1]
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Answer:

IT WOULD BE 2.5 IN decimal form or it would be 5/2 and it is equivalent to 2 and 1/2

Step-by-step explanation:

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