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mojhsa [17]
2 years ago
10

If the shaded sector is 75m what would the area be of the circle? A. 30 B. 36 C.144 D. 108

Mathematics
1 answer:
fredd [130]2 years ago
8 0
The correct answer is letter B
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Solve 2x2 + 12x − 14 = 0 by completing the square, options: A. 2(x + 6)2 = 26; x = −6 + square root 13, x = −6 − square root 13
musickatia [10]
I just solved this one
anothe way is undistribute the 2 first and move -14 to side
2(x^2+6x)-14=0
comlete the squer inside and add negative
2(x^2+6x+9-9)-14=0
factor perfect square
2((x+3)^2-9)-14=0
distribute
2(x+3)^2-18-14=0
2(x+3)^2-32=0
add 32 both sides
2(x+3)^2=32
divide 2
(x+3)^2=16
sqrt both sides
x+3=+/-4
minus 3
x=-4-3 or 4-3
x=1 or -7

answer is C

8 0
3 years ago
Read 2 more answers
What is the least common multiple of 6 and 16?<br> lcm/6, 16)
Step2247 [10]

Answer:

48

Step-by-step explanation:

multiples of 6: 6 12 18 24 30 36 42 48 54 60

multiples of 16: 16 32 48 64

lowest one is 48

8 0
2 years ago
Problem 2: For a recent year, the mean fare to fly from Charlotte, North Carolina to Chicago Illinois, on a discount ticket was
Maru [420]

Answer:

Step-by-step explanation:

n = 12

The mean of the set of data given is

Mean, x = (286 + 290 + 285 + 291 + 287 + 275 + 262 + 289 + 274 + 276 + 297 + 262)/12 = 281.2

Standard deviation = √(summation(x - mean)²/n

Summation(x - mean)² = (286 - 281.2)^2 + (290 - 281.2)^2 + (285 - 281.2)^2 + (291 - 281.2)^2 + (287 - 281.2)^2 + (275 - 281.2)^2 + (262 - 281.2)^2 + (289 - 281.2)^2 + (274 - 281.2)^2 + (276 - 281.2)^2 + (297 - 281.2)^2 + (262 - 281.2)^2 = 1409.68

Standard deviation, s = √(1409.68/12) = 10.8

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

1) For the null hypothesis,

H0: µ = 290

For the alternative hypothesis,

H1: µ < 290

This is a left tailed test.

2) Since the number of samples is small and no population standard deviation is given, the distribution is a student's t.

Since n = 12,

Degrees of freedom, df = n - 1 = 12 - 1 = 11

t = (x - µ)/(s/√n)

Where

x = sample mean = 281.2

µ = population mean = 290

s = samples standard deviation = 10.8

t = (281.2 - 290)/(10.8/√12) = - 2.82

Test statistic = - 2.82

3) The decision rule is to reject the null hypothesis if the significance level is greater than the p value.

4) We would determine the p value using the t test calculator. It becomes

p value = 0.0083

5) Since alpha, 0.01 > than the p value, 0.0083, then we would reject the null hypothesis. Therefore, At a 1% level of significance, the sample data showed significant evidence that the mean fare has decreased.

3 0
3 years ago
Help meh plz im a dum dum head
kolbaska11 [484]
Ur not dumb I’m the dumb one XD
8 0
2 years ago
Read 2 more answers
Which of the fractions below are equivalent to 2/3​
steposvetlana [31]
Theres nothing there, it's just the question
6 0
2 years ago
Read 2 more answers
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