For f (x) = 3x+1 and g(x) = x? -6,find (7.8)(x).

Mathematics

1 answer:

Vitek1552 [10]3 years ago

5 0

I believe the answer is C

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Please i need help :(

Nezavi [6.7K]

Answer:

37 units

Step-by-step explanation:

$\boxed{distance = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2} }}$

Using the distance formula above,

distance between (15, -17) and (-20, -5)

$= \sqrt{[15 - ( - 20)]^{2} + [ - 17 - ( - 5)] {}^{2} } \\ = \sqrt{(15 + 20)^{2} + ( - 17 + 5)^{2} } \\ = \sqrt{35 ^{2} + ( - 12) {}^{2} } \\ = \sqrt{1225 + 144} \\ = \sqrt{1369} \\ = 37 \: units$

7 0

2 years ago

Question 1: 3/4n+16=2-1/8n. Show work plzz for all i need help due tomorrow!!!

Bezzdna [24]

1) Multiply everything by 8. It clears the fractions.
It gives you 6n + 128 =16 - n
You add the -n to the other side of the equation.
It gives you 7n + 128= 16
You then subtract 128 from 16.
It gives you 7n= -112
You divide everything by 7
It gives you n=-17

7 0

3 years ago

A flagpole broke in a storm. It was originally 81 8181 feet tall. 28 2828 feet are still sticking straight out of the ground, wh

solong [7]

Answer:

The end of the flagpole is 50.79 ft away from the base of the pole.

Step-by-step explanation:

The problem is represented by the diagram below.

The broken flagpole forms the shape of a right angled triangle. We need to find one of the sides of the triangle, the adjacent (x).

The hypotenuse is the broken part of the flagpole (53 ft), while the opposite is the part of the flagpole that is still stuck to the ground (28 ft).

Using Pythagoras theorem, we have that:

$hyp^2 = adj^2 + opp^2$