Answer:
The graph in the attached figure
Step-by-step explanation:
we have

Remember that in a quotient, the denominator cannot be equal to zero
so
The value of x cannot be equal to x=-2
Simplify the expression
Using a graphing tool
The roots of the quadratic equation in the numerator are
x=-2 and x=1
so

Simplify the denominator

substitute in the original expression

Simplify


Is the equation of a line
The y-intercept is the point (0,-3) (value of the function when x is equal to zero)
The x-intercept is the point (1,0) (value of x when the value of the function is equal to zero)
Graph the line, but remember that the value of x cannot be equal to -2
The graph in the attached figure
Answer:
a. Required system of equations is:
c+p = 10
5c+4p = 46
b. 6 cakes were sold
Step-by-step explanation:
Let p be the number of pies and c be the number of cakes.
Then according to given statement " the store sold 10 baked goods"

And
"A cake costs $5 and a pie costs $4"

Using equation 1,

Putting this value of c in equation 2:

Putting p = 4 in equation 1

Hence,
a. Required system of equations is:
c+p = 10
5c+4p = 46
b. 6 cakes were sold
Answer:
i dont know.
Step-by-step explanation:
pls make it brainliest