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artcher [175]
3 years ago
14

You have 10 green marbles, 30 white marbles, and 25 black marbles. What’s the probability of NOT selecting a green marble?

Mathematics
1 answer:
prohojiy [21]3 years ago
4 0

Answer

Its around 30% but their is about 55 other marbles

Step-by-step explanation:

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Haley bought 8 pencils and 3 folders for $10.39. Nicole bought 5 pencils and 4 folders for $10.51. How much does a folder cost?
cupoosta [38]

Answer:

$1.89

Step-by-step explanation:

1) 8p+3f=$10.39

2) 5p+4f=$10.51

where p represents pencil & f represents folder.

multiply the first equation by 5 and the second equation by 8.

40p+15f=$51.95

40p+32f=$84.08

Subtract

17f=$32.13

f=$32.13/17 =$1.89

6 0
3 years ago
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-100 - ___= 65<br> A. 35<br> B. 65<br> C. -35<br> D. -165
Softa [21]

Answer:

D

Step-by-step explanation:

If you subtract -165 from -100 you will get 65.

4 0
3 years ago
What percent of the people get less than eight hours of sleep each night? [Type your answer as a number.]
Shalnov [3]

Answer:

More than 35%

Step-by-step explanation:

4 0
4 years ago
Read 2 more answers
9. A large electronic office product contains 2000 electronic components. Assume that the probability that each component operat
Marysya12 [62]

Answer:

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

Step-by-step explanation:

For each component, there are only two possible outcomes. Either it works correctly, or it does not. The probability of a component falling is independent from other components. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

In this problem we have that:

n = 2000, p = 1-0.995 = 0.005

Approximate the probability that five or more of the original 2000 components fail during the useful life of the product.

We know that either less than five compoenents fail, or at least five do. The sum of the probabilities of these events is decimal 1. So

P(X < 5) + P(X \geq 5) = 1

We want P(X \geq 5)

So

P(X \geq 5) = 1 - P(X < 5)

In which

P(X < 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{2000,0}.(0.005)^{0}.(0.995)^{2000} = 0.000044

P(X = 1) = C_{2000,1}.(0.005)^{1}.(0.995)^{1999} = 0.000445

P(X = 2) = C_{2000,2}.(0.005)^{2}.(0.995)^{1998} = 0.002235

P(X = 3) = C_{2000,3}.(0.005)^{3}.(0.995)^{1997} = 0.007480

P(X = 4) = C_{2000,4}.(0.005)^{4}.(0.995)^{1996} = 0.018765

P(X < 5) = P(X = 0) + `P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) = 0.000044 + 0.000445 + 0.002235 + 0.007480 + 0.018765 = 0.0290

P(X \geq 5) = 1 - P(X < 5) = 1 - 0.0290 = 0.9710

97.10% probability that five or more of the original 2000 components fail during the useful life of the product.

4 0
3 years ago
How can you isolate the term -5m
AleksandrR [38]

Answer:

subtract 9 on both sides.

Step-by-step explanation:

-5m+9=12 --> -5m=7

8 0
2 years ago
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