Answer:
0.15-0.75p? YES
-0.45-0.6+0.75P? NO
-3(-0.05+0.25p)? YES
-3(0.15)+(-3)(0.2)+(-3)(0.25p)? NO
Step-by-step explanation:
-3(0.15-0.2+0.25p)
=-0.45+0.6-0.75p
=0.15-0.75p
1. 0.15-0.75p=0.15-0.75p? YES
2. -0.45-0.6+0.75P=0.15-0.75p?
-1.05+0.75p=0.15-0.75p? NO
3. -3(-0.05+0.25p)=0.15-0.75p?
0.15-0.75=0.15-0.75p? YES
4. -3(0.15)+(-3)(0.2)+(-3)(0.25p)=0.15-0.75p?
-0.45-0.6-0.75p=0.15-0.75p?
-1.05-0.75p=0.15-0.75p? NO
Answer: The Answer is 10
Step-by-step explanation:
Answer:
Answer (a) is correct
Step-by-step explanation:
This is not the same function that was given to you in the problem.
As you have typed it, this function is linear. The one in the homework problem is exponential.
We will ignore the linear function h(t) = 0.32 - 0.5t.
We will focus on h(t) = 0.32 - 0.5^t.
If t = 0, then 0.5^t = 0.5 ^0 = 1, and so h(0) = 0.32 - 1 = -0.68 => (0, -0.68)
Continuing with a few other t values chosen at random:
h(1) = -0.18
h(2) = 0.07
Notice that h is increasing as x increases!
h(4) = 0.2575
and so on.
answer A is the correct one.
h(1) = 0.32 - 0.5^1 = 0.32 - 0.5 = -0.18
Answer:
Step-by-step explanation:
Using the distance formula: 
substitute
