Question

To 225 mL of a 0.80M solution of KI, a student adds enough water to make 1.0L of a more dilute KI solution. What is the molarity of the new solution? A.180M B. 2.8M C. 0.35M D. 0.18M

Answer 1

Hope this helps you!

Answer 2

Answer: The correct answer is Option D

Explanation:

To calculate the molarity of the diluted solution, we use the equation:

$M_1V_1=M_2V_2$

where,

$M_1\text{ and }V_1$ are the molarity and volume of the concentrated solution

$M_2\text{ and }V_2$ are the molarity and volume of diluted solution

We are given:

Conversion factor: 1 L = 1000 mL

$M_1=0.80M\\V_1=225mL\\M_2=?M\\V_2=1L=1000mL$

Putting values in above equation, we get:

$0.80\times 225=M_2\times 1000\\\\M_2=0.18M$

Hence, the correct answer is Option D