This reaction contains pure solids which are not considered when writing out equilibrium constant expressions.
O2...........SO2
I 2.9...........0
C -x.......... +x
E 2.9-x........ x
Q=0/2.9 = 0 ---->Q<K Reaction will go to the right
Since the coefficients are all 1, I won't bother putting in the exponents.
k=B/A
1.5= x / (2.9-x)
4.35 - 1.5x = x
2.5x = 4.35
x= 1.74
plug back in ice chart
2.9 - 1.74
=1.16
=1.2 ANSWER
Contains only Carbon and Hydrogen.
(3) CH3CH3
Answer:
This is a coal combustion process and we will assume
Inlet coal amount = 100kg
It means that there are
15kg of H2O, 2kg of Sulphur and 83kg of Carbon
Now to find the mole fraction of SO2(g) in the exhaust?
Molar mass of S = 32kg/kmol
Initial moles n of S = 2/32 = 0.0625kmols
Reaction: S + O₂ = SO₂
That is 1 mole of S reacts with 1 mole of O₂ to give 1 mole of SO₂
Then, it means for 0.0625 kmoles of S, we will have 0.0625 kmole of SO2 coming out of the exhaust
The mole fraction of SO2(g) in the exhaust=0.0625kmols
Explanation:
Answer:
Because the freezing point of pure water is 0°C, the sucrose solution freezes at ... where K b is the molal boiling point constant and m is the concentration of the solute ... Calculate the total ionic molality of a solution of 50.0 grams of aluminum.
Explanation: