the Percentage yield for the reaction = 48.8%
What is Percentage yield ?
The % ratio of the theoretical yield to the actual yield is known as the percent yield. It is calculated as the theoretical yield multiplied by 100% divided by the experimental yield. The percent yield is 100% if the theoretical and actual yields are equal. Because the real yield is frequently lower than the theoretical value, percent yield is typically lower than 100%. This may be due to incomplete or conflicting reactions or sample loss during recovery. If the percent yield is more than 100%, more sample than expected was retrieved from the reaction.
4 P + 3 O2 = P4O6
moles P = 75.3 g / 30.9738 g/mol= 2.43
moles O2 required = 2.43 x 3 / 4=1.82
actual moles O2 = 38.7 g /32 g/mol=1.21 so O2 is the limiting reactant
theoretical moles P4O6 = 1.21 / 3=0.403
theoretical mass P4O6 = 0.403 mol x 219.895 g/mol=88.6 g
% yield = 43.3 x 100/ 88.6 = 48.8 %
the Percentage yield for the reaction = 48.8%
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Answer:
Option D
Explanation:
Hydronium ion concentration is a measure of pH of a solution.
The mathematical equation for the same is [H3O+] = 10-pH
OR
[H3O+] = antilog (- pH)
Hence, option D is correct
- Glucose = C₆H₁₂O₆.
- Atomic mass of C = 12 u
- Atomic mass of H = 1 u
- Atomic mass of O = 16 u
- Therefore, the molecular mass of glucose
- = (6 × Atomic mass of C) + (12 × Atomic mass of H) + (6 × Atomic mass of O)
- = (6 × 12) + (12 × 1) + (6 × 16) u
- = 72 + 12 + 96 u
- = 180 u
<u>Answer</u><u>:</u>
<u>1</u><u>8</u><u>0</u><u> </u><u>u</u>
Hope you could understand.
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