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Mathematics

1 answer:

PolarNik [594]2 years ago

5 0

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What is 65,759.59 rounded to the nearest tenth

coldgirl [10]

65,759.60

Hope this helps

6 0

3 years ago

3 orange picks for every 2 green. if there are 25 picks in all, how many picks are orange?

Marta_Voda [28]

3+2=5
25÷5=5
5×3=15
There are 15 Orange picks.

8 0

3 years ago

Read 2 more answers

Is anyone able to answer this for me? GIVING BRAINLIEST! hurry!

svetoff [14.1K]

Nicoles pattern:

1
5
17
53
161

Ian’s pattern:

0
1
3
7
15

Ordered pair:

(1, 0)
(5, 1)
(17, 3)
(53, 7)
(161, 15)

Table 1 -

Sequence 1:

9
11
13
15
17

Sequence 2:

5
8
11
14
17

Ordered pair:

(9, 5)
(11, 8)
(13, 11)
(15, 14)
(17, 17)

Table 2 -

Sequence 1:

20
16
12
8
4

Sequence 2:

20
17
14
11
8

Ordered pair:

(20, 20)
(16, 17)
(12, 14)
(8, 11)
(4, 8)

Table 3 -

Sequence 1:

1
3
7
15
31

Sequence 2:

40
24
16
12
10

Ordered pair:

(1, 40)
(3, 24)
(7, 16)
(15, 12)
(31, 10)

5 0

2 years ago

Two cards are drawn without replacement from a standard deck of 52 playing cards. What is the probability of choosing a king and

STALIN [3.7K]

Answer:

0.0181 probability of choosing a king and then, without replacement, a face card.

Step-by-step explanation:

A probability is the number of desired outcomes divided by the number of total outcomes.

Probability of choosing a king:

There are four kings on a standard deck of 52 cards, so:

$P(A) = \frac{4}{52} = \frac{1}{13}$

Probability of choosing a face card, considering the previous card was a king.

12 face cards out of 51. So

$P(B|A) = \frac{12}{51}$

What is the probability of choosing a king and then, without replacement, a face card?

$P(A \cap B) = P(A)P(B|A) = \frac{1}{13} \times \frac{12}{51} = \frac{1*12}{13*51} = 0.0181$

0.0181 probability of choosing a king and then, without replacement, a face card.

5 0

3 years ago

Matthew drove 189 miles in 7 hours. If he continued at the same rate, how long would

Viktor [21]

The answer is 594 miles

4 0

3 years ago