3 years ago

I need help solving these problems.

Mathematics

1 answer:

PolarNik [594]3 years ago

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I can’t see the picture very well

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Factor –8x3 – 2x2 – 12x – 3 by grouping. what is the resulting expression? (2x2 – 3)(4x 1) (–2x2 – 3)(–4x 1) (2x2 – 3)(–4x 1) (–

myrzilka [38]

The factors of the expression are $\rm (4x+1)(-2x^2-3)$

<h3>How to find factors in the expression?</h3>

First group the first two terms and the last two terms together respectively.

The factors of the expression are given by;

$\rm -8x^3 -2x^2 - 12x - 3\\\\-2x^2(4x+1)-3(4x+1)\\\\(4x+1)(-2x^2-3)$

Hence, the factors of the expression are $\rm (4x+1)(-2x^2-3)$ .

To know more about factors click the link given below.

brainly.com/question/9645056

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A. Steven wrote an expression with 2 terms. The second term, which is the whole number 7, is subtracted from the first term. The

bulgar [2K]

Answer:

Part a)

Steve's expression is $2(2x+5)^{2}-7$

For x=3, the expression is equal to $235$

Part b)

Jasmine's expression is

$(3x^{2})+(25x)$

For x=2, the expression is equal to $62$

Step-by-step explanation:

Part a)

Let

n-----> the first term

The expression is

$(n-7)$

$n=2(2x+5)^{2}$

substitute

Steve's expression is

$2(2x+5)^{2}-7$

Evaluate for x=3

$2(2(3)+5)^{2}-7=242-7=235$

Part b)

Let

n-----> the first term

Jasmine's expression is

$(3x^{2})+(25x)$

Evaluate for x=2

$(3(2)^{2})+(25(2))=12+50=62$

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