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nata0808 [166]
3 years ago
12

An amusement park charges $27 for adult tickets (a) and $24 for children's tickets (c). Last Friday the amusement park sold 272

tickets and collected $7,137. Which of the following systems of equations is a correct representation of this data?
Chemistry
2 answers:
Vaselesa [24]3 years ago
7 0
Try using a calculator
Lapatulllka [165]3 years ago
4 0

Answer:

a+c=272

27a+24c=7,137

Explanation: Hope this helps!!!

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A quantity of water is heated from 25.0°C to 36.4°C by absorbing 325 J of heat energy. If the specific heat of water is 4.18 J /
Arlecino [84]

Answer:

6,8 g

Explanation:

c = 4.18 J/(g * °C) = 4180 J / (kg * °C)

t_{1} = 25 °C

t_{2} = 36,4 °C

Q = 325 J

The formula is: Q = c * m * (t_{2} - t_{1})

m = \frac{Q}{c * (t_{2} - t_{1} )}

Calculating:

m = 325 / 4180 * (36,4 - 25) ≈ 0,0068 kg = 6,8 g

6 0
3 years ago
What is the mass spectrom​
NARA [144]

Answer:

Here's your Answer

Explanation:

the mass spectrum is the graphical representation of the ion abundance versus the mass to charge of the ions separated in mass spectrometer

7 0
3 years ago
If a 125 gms of radioactive element has a half life of 60 min how many half lives will it go through to become 3.90625 gms
Sonja [21]

Answer:

  • 5

Explanation:

Let the number of half lives be x

<u>Solve this equation to find the value of x:</u>

  • 125*(1/2)ˣ = 3.90625
  • (0.5)ˣ = 3.90625 / 125
  • (0.5)ˣ = 0.03125
  • log (0.5)ˣ  = log 0.03125
  • x =  log 0.03125 / log 0.5
  • x = 5

4 0
2 years ago
2-phosphoglycerate(2PG) is converted to phosphoenolpyruvate (PEP) by the enzyme enolase. The standard free energy change(deltaGo
pogonyaev

Answer:

The correct option is: (D) -2.4 kJ/mol

Explanation:

<u>Chemical reaction involved</u>: 2PG ↔ PEP

Given: The standard Gibb's free energy change: ΔG° = +1.7 kJ/mol

Temperature: T = 37° C = 37 + 273.15 = 310.15 K    (∵ 0°C = 273.15K)

Gas constant: R = 8.314 J/(K·mol) = 8.314 × 10⁻³ kJ/(K·mol)     (∵ 1 kJ = 1000 J)

Reactant concentration: 2PG = 0.5 mM

Product concentration: PEP = 0.1 mM

Reaction quotient: Q_{r} =\frac{\left [ PEP \right ]}{\left [ 2PG \right ]} = \frac{0.1 mM}{0.5 mM} = 0.2

<u>To find out the Gibb's free energy change at 37° C (310.15 K), we use the equation:</u>

\Delta G = \Delta G^{\circ } + 2.303 R T log Q_{r}

\Delta G = 1.7 kJ/mol + [2.303 \times (8.314 \times 10^{-3} kJ/(K.mol))\times (310.15 K)] log (0.2)

\Delta G = 1.7 + [5.938] \times (-0.699) = 1.7 - 4.15 = (-2.45 kJ/mol)

<u>Therefore, the Gibb's free energy change at 37° C (310.15 K): </u><u>ΔG = (-2.45 kJ/mol)</u>

4 0
3 years ago
Calculate the number of molecules of sulphur S8 in 8 gram of solid Sulphur​
Luden [163]

Answer:

12gram

Explanation:

test told me

7 0
3 years ago
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