Answer:
Kp = (Partial pressure H₂O) . (Partial Pressure Cl₂)² / Partial pressure O₂ . (Partial Pressure HCl)⁴
Explanation:
This is the reaction:
4 HCl (g) + O₂ (g) ⇒ 2 Cl₂ (g) + 2 H₂O(g)
Kp = (Partial pressure H₂O) . (Partial Pressure Cl₂)² / Partial pressure O₂ . (Partial Pressure HCl)⁴
"windweathered" because the use of wind weathering would bring the sand all around and it would be wind weathered
Answer:
800.0 mL.
Explanation:
- To solve this problem; we must mention the rule states the no. of millimoles of a substance before and after dilution is the same.
<em>(MV)before dilution of HCl = (MV)after dilution of HCl</em>
M before dilution = 12.0 M, V before dilution = 100.0 mL.
M after dilution = 1.5 M, V after dilution = ??? mL.
∵ (MV)before dilution of HCl = (MV)after dilution of HCl
∴ (12.0 M)(100.0 mL) = (1.5 M)(V after dilution of HCl)
<em>∴ V after dilution of HCl = (12.0 M)(100.0 mL)/(1`.5 M) = 800.0 mL.</em>
6) Na2 SO4
7)nonmetallic elements
10)mass
11) mole
* sorry I didn't know Q. 8/9
Answer:
it's not
Explanation:
gasoline is not soluble in water in gasoline is a complex mixture of nonpolar compounds such as long-chain hydrocarbons etc water is a polar molecule as a result of the gasoline molecules cannot enter water and borla solution
