Answer:
re clear. Try to convey your meaning as simply as possible. Don't over-write or use exorbitant language. ...
Are complete. Include all relevant information. Think about the situation from your readers' perspective. ...
Are correct. Always proofread before sending any message.
Explanation:
The section "Cute Beavers Also Cause Trouble" that is MOST important to include in the section's summary is They can also be moved or killed if they cause trouble.
<h3>Are beavers a threat to humans?</h3>
Beavers are not to be creature which are not dangerous if left to be alone. But, they will often confront any threat when they are trapped or cornered, and thus a beaver will attack a human.
Hence, The section "Cute Beavers Also Cause Trouble" that is MOST important to include in the section's summary is They can also be moved or killed if they cause trouble.
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The standard state formation reaction is a chemical reaction in which one moles of substance in its standard state is formed from its constituent element in their standard state.All the substance must be in their most stable state at 100kpa and 25 degrees celsius.
therefore for HF is
1/2H2 +1/2F2 =HF
Clutch Prep
Ch.2 - Atoms & ElementsSee all chapters
Atomic Theory
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Solution: Which of the following chemical reactions is/are NOT possible according to Dalton's atomic theory?a. reaction 1: CCl4 → CH4b. reaction 2: N2 + 3H2 → 2NH3c. reaction 3: 2H2 + O2 → 2H2O + Au
Problem
Which of the following chemical reactions is/are NOT possible according to Dalton's atomic theory?
a. reaction 1: CCl4 → CH4
b. reaction 2: N2 + 3H2 → 2NH3
c. reaction 3: 2H2 + O2 → 2H2O + Au
Answer: 120g/mol
Explanation:
The first step we are to take is to calculate the freezing point depression of the solution.
ΔT(f) = freezing point of pure solvent - freezing point of solution
ΔT(f) = 5.48 - 3.77
ΔT(f) = 1.71°C
Next we are to calculate the molal concentration of the solution using freezing point depression
ΔT(f) = K(f) * m
m = ΔT(f)/K(f)
m = 1.71/5.12
m = 0.333 molal
Now, we calculate the molecular weight of the unknown...
m = 0.333 mol = 0.333 mol X per kg of benzene
moles of X = 0.333 mol of X per kg of benzene * 0.5kg of benzene
moles of X = 0.1665
molecular weight of X = 20g of X/0.1665
molecular weight of X = 120/mol