Answer:
None of these
Explanation:
The questions asks us to find the amount of sodium chloride formed (in grams) when 1.125 X 10^45 molecules of chlorine gas reacts with sodium.
We start by converting the molecules of chlorine gas to moles using Avogadro's number:
1.125 X 10^45 molecules Cl2 X 1 mol Cl2 / 6.022 X 10^23 = 1.87 X 10^21 mol
From here we can set up a BCA table, assuming that we have excess Sodium to react with: We have to assume that Cl2 is the limiting reactant.
2Na + Cl2 ----> 2NaCl
B . excess 1.87 X 10^21 0
C -3.74 X 10^21 -1.87 X 10^21 + 3.74 X 10^21
A X Amount 0 3.74 X 10^21
Now we have 3.74 X 10^21 moles of NaCl that we have to convert to grams:
We can use the molar mass of sodium chloride to accomplish this:
3.74 X 10^21 moles NaCl X 58.44 g NaCl / 1 mol NaCl = 2.18 X 10^23 g NaCl
Answer: None of these
The right answer is
Table A Organic solvent
No Perfume No Fuel No Anesthetic No Adhesive Yes
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Explanation:
Wii Wii sennò archivi accompagnatori hahahhaa quietanza Wiiplay Stone Sour just boo-boo
Answer:
B)−6,942 J
/mol
Explanation:
At constant temperature and pressure, you cand define the change in Gibbs free energy, ΔG, as:
ΔG = ΔH - TΔS
Where ΔH is enthalpy, T absolute temperature and ΔS change in entropy.
Replacing (25°C = 273 + 25 = 298K; 25.45kJ/mol = 25450J/mol):
ΔG = ΔH - TΔS
ΔG = 25450J/mol - 298K×108.7J/molK
ΔG = -6942.6J/mol
Right solution is:
<h3>B)−6,942 J
/mol</h3>
