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wel
2 years ago
13

A hydrogen atom in an excited state can be ionized with less energy than when it is in its ground state. What is n for a hydroge

n atom if 0.544 eV of energy can ionize it?
Chemistry
1 answer:
Molodets [167]2 years ago
5 0

Explanation:

It is known that formula for the ionization energy of hydrogen atom is as follows.

               E = \frac{13.6 eV}{n^{2}}

or,          n = \sqrt{\frac{13.6}{E}}

The value of energy is given as 0.544 eV. Therefore, we will calculate the value of n as follows.

                   n = \sqrt{\frac{13.6}{E}}

                      = \sqrt{\frac{13.6}{0.544 eV}}

                      = 5

Thus, we can conclude that n equals to 5 for a hydrogen atom if 0.544 eV of energy can ionize it.

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(-1 )       (-1)             (0)

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5. balance hydrogen by adding water molecules

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= Cu -----> Cu2+ + 2e-

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Combined equation  = Cu + 2NO3- + 4H+ ---------> Cu2+ + 2NO2 + 2H20

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