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Kobotan [32]
4 years ago
12

Onsider the enlargement of the triangle with a scale factor of 8 2 triangles have corresponding side lengths of 8 centimeters an

d 64 centimeters. Side A corresponds with a side with length of 2 centimeters. Side A = 2(8) = 16 cm. What is the length of side B?
Mathematics
2 answers:
docker41 [41]4 years ago
8 0

Answer: 8

Step-by-step explanation:

I ALREADY TOOK THE TEST

ahrayia [7]4 years ago
3 0

Answer: Incomplete question

Step-by-step explanation: The question does not provide a diagram, and that makes it difficult to determine which side is labelled as B. Nevertheless I will give you clues to help you answer your question by explaining  this topic which is SIMILAR TRIANGLES.

When you have been given two triangles with a scale factor, the scale factor is an important part of answering the question eventually.

Consider a triangle which I shall call triangle 1, with sides abc and another triangle ABC, which I shall call triangle 2. The scale factor is 8, which means triangle 1 can be enlarged into a similar triangle by simply multiplying any corresponding side by 8. Hence, if in triangle abc, you have a side that measures 8 centimetres, the corresponding side in triangle ABC would be 8 times 8 which equals 64 centimetres.

The question states that side A corresponds with a side measuring length 2 centimetres. That means side A is derived as 2 times 8 which equals 16 centimetres, as explained above (and as shown in the question). Therefore side B which is yet unknown shall also be the corresponding side in triangle 1 multiplied by 8.

Since the corresponding side was not stated, I shall assume for the sake of explanation that the corresponding side is 10 centimetres. That means, side B would now be derived as 10 times 8 which equals 80 centimetres.

These can be expressed mathematically as follows;

If A = 16, a = 2 and b = 10 then B would be calculated as follows;

A/a = B/b

16/2 = B/10

By cross multiplication, you now have

16 * 10 = 2 * B

160/2 = B

80 = B

Following these steps along with the explanations, the length of side B can be derived if the value of its corresponding side is given or a diagram is provided.

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➷ Just divide them:

1731/2 = 865.5

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3 0
3 years ago
A box contains different-colored marbles. If P(blue) = 1, P(green) = 4, and P(blue and green) = 12, which state
riadik2000 [5.3K]

Answer:

Not 100 percent sure but i think the correct answer is the last one.

Step-by-step explanation:

I know that the answer is either the last one or before the last because they are dependent on each other. This is because the probability of both increases when they are added together. The more you have the more likely to get one of them. I went for the last one because i think that the value of together is greater than when they are added.

Again, not 100 percent sure, tried to give it my best shot.

Hope this helps.

7 0
3 years ago
The area on a wall covered by a rectangular poster is 270 square inches. The length of the poster is 1.2 times longer than the w
forsale [732]

Answer:

Length = 18 in

Width = 15 in

Step-by-step explanation:

We have that the area of a rectangle is:

A = L * W

but L = 1.2 * W

A = 1.2 * (W ^ 2)

1.2 * (W ^ 2) = 270

(W ^ 2) = 270 / 1.2

W ^ 2 = 225

Therefore, W is equal to:

W = 225 ^ (1/2)

W = +/- 15, but only +15 makes sense

W = 15

Now for L:

L = 1.2 * 15

L = 18

A = 15 * 18 = 270 in ^ 2

4 0
3 years ago
A baby's crib has an area of 690:square inches and a perimeter of 106 inches.What are the dimensions of the crib
KengaRu [80]

Answer:

The crib is 30 inches wide and 23 inches long.

Step-by-step explanation:

Assuming that the crib is rectangular, then the crib has a length L and a width W.

And remember that for a rectangle of width W and length L, the perimeter is:

P = 2*L + 2*W = 2*(L + W)

And the area is:

A = L*W

In this case, the perimeter is 106 in, then:

P = 106in = 2*(L + W)

And we also know that the area is 690 in^2

Then:

A = 690in^2 = L*W

Then we have a system of equations:

106in = 2*(L + W)

690in^2 = L*W

To solve this, first, we need to isolate one of the variables in one of the equations.

Let's isolate L in the first one:

106in/2 = L + W

53 in = L + W

53in - W = L

Now we can replace this in the other equation:

690in^2 = L*W = (53in - W)*W = 53in*W - W^2

690in^2 =  53in*W - W^2

Now we need to solve this for W.

This is a quadratic equation:

W^2 - 53in*W + 690 in^2 = 0

The solutions of this equation are given by Bhaskara's formula:

W = \frac{-(-53in)\pm \sqrt{(-53in)^2 - 4*1*(690in^2)}  }{2} =  \frac{57in \pm 7in}{2}

Then the two possible solutions of W are:

W = (53in + 7in)/2 = 30in

W = (53in - 7in)/2 = 23in

We can choose any one of these, so let's choose W = 30in

If we replace this in the equation: "53in - W = L"

We can find the value of L:

53in - 30in = 23in = L

Then we have:

W = 30in

L = 23in

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Lilit [14]
The answer is C) 66 yards
3 0
4 years ago
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