Question

How many grams of hydrogen are needed to produce 1.80g of water according to this equation?

Answer 1

Answer:

0.2g of hydrogen is needed to produce 1.80g of water

Explanation:

$H_{2}+O_{2} \to 2H_{2}O$

No. of moles of water$= \frac{Weight}{Molecular \, weight}$

From given values,

Weight of water $=1.80g$

Molecular weight of water $=18g$

$\therefore$ No. of moles of water$=\frac{1.80}{18}=0.1$

From equation, it is clear that 2 moles of water can be formed by 2 moles of $H_{2}$

Hence, 0.1 mole of water can be formed from 0.1 mole of $H_{2}$

Now,

No. of moles of $H_{2} = \frac{Weight}{Molecular \, weight}$

$\Rightarrow weight \,of\, H_{2}=No.\,of\,moles \times Molecular\,weight \\ =0.1 \times 2=0.2g$