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julia-pushkina [17]
3 years ago
6

The molar solubility of magnesium carbonate Mg(CO3) is 1.8 x 10-4 mol/L. What is the Ksp for this compound?

Chemistry
1 answer:
irina [24]3 years ago
8 0

Answer:

The Ksp for this compound is 3.24 * 10^-8

Explanation:

Step 1: Data given:

Molar solubility of MgCO3 = 1.8 * 10^-4 mol /L

Step 2: Calculate molarity

For an insoluble compound, its molar solubility tells you how many moles of the compound can be dissolved per liter of aqueous solution before reaching saturation.

In this case, it means that we can only dissolve  1.8 * 10^-4 moles  in a liter of water at that temperature.

Moles Mg^2+ =  1.8 * 10^-4 moles

Moles CO3^2- =  1.8 * 10^-4 moles

Since we're working with one liter of solution, we can say the molarity:

[Mg^2+] =  1.8 * 10^-4 M

[CO3^2-] =  1.8 * 10^-4 M

Step 3: Calculate Ksp

Ksp = [Mg^2+]*[CO3^2-]

Ksp =  1.8 * 10^-4 *  1.8 * 10^-4

Ksp = 3.24 * 10^-8

The Ksp for this compound is 3.24 * 10^-8

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Answer: Atomic number, atomic mass, and relative atomic mass

Explanation:

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3 years ago
Define and then describe the difference between a polar covalent bond, nonpolar covalent bond and ionic bond.
Romashka [77]
Polar covalent bond-  a bond where atoms are unevenly shared due to a larger difference in electronegativity of the bonded elements.

Non-polar covalent bond- These are bonds between elements with a low difference in electronegativity. Electrons are shared equally in these bonds between the elements.

Ionic bonds- have such  large difference in electronegativity that they take/give electrons to the element they are bonded to. They do not share electrons at all. Bonds between a non-metal and a metal.
3 0
3 years ago
Question 11. Identify the reducing agent <br> Sn+2 + AG 0 —&gt; Sn0 + Ag+
Temka [501]

Answer:

Ag 0 is the reducing agent.

Explanation:

Reducing -> gaining electrons

Oxidizing -> losing electrons

Ag lost electrons (became more positive) since it went from a 0 charge to a +1 charge. Therefore it was oxidized. Ag+ is the oxidized product. Reactants that create an oxidized product are called reducing agents. This would make Ag 0 the reducing agent in this reaction.

4 0
2 years ago
A gas occupies 56 L at 73°C. What volume will the gas occupy if the temp. cools to 0°C?
vova2212 [387]

Answer:

44.2 L

Explanation:

Use Charles Law:

\frac{V1}{T1} =\frac{V2}{T2}

We have all the values except for V₂; this is what we're solving for. Input the values:

\frac{56 L}{346K} =\frac{V2}{273K}   -  make sure that your temperature is in Kelvin

From here, we need to get V₂ by itself. To do this, multiply by 273 on both sides:

\frac{56*273}{346} = V2

Therefore, V₂ = 44.2 L

It's also helpful to know that temperature and volume are linearly related. So, when temperature drops, so will volume and vice versa.

7 0
2 years ago
You have 16.7 grams of hydrogen and 15.4 grams of oxygen in a synthesis rxn. Which is the limiting reagent?
sleet_krkn [62]

Answer:

oxygen is limiting reactant

Explanation:

Given data:

Mass of hydrogen = 16.7 g

Mass of oxygen = 15.4 g

Limiting reactant = ?

Solution:

Chemical equation:

2H₂ + O₂   →   2H₂O

Number of moles of hydrogen:

Number of moles = mass/ molar mass

Number of moles = 16.7 g/ 2 g/mol

Number of moles = 8.35 mol

Number of moles of oxygen:

Number of moles = mass/ molar mass

Number of moles = 15.4 g/ 32 g/mol

Number of moles = 0.48 mol

Now we will compare the moles of both reactant with product,

                 

                             H₂           :          H₂O

                              2            :            2

                             8.35        :            8.35

                             O₂           :          H₂O

                               1            :            2

                             0.48        :        2×0.48 = 0.96 mol

The number of moles of water produced by oxygen are less so it will limiting reactant.

3 0
3 years ago
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