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emmasim [6.3K]
3 years ago
9

Determine the formulas for these ionic compounds. copper(I) bromide: copper(I) oxide: copper(II) bromide: copper(II) oxide: iron

(III) bromide: iron(III) oxide: lead(IV) bromide: lead(IV) oxide:
Chemistry
1 answer:
joja [24]3 years ago
4 0

Answer:

copper(I) bromide: CuBr

copper(I) oxide: Cu₂O

copper(II) bromide: CuBr₂

copper(II) oxide: CuO

iron(III) bromide: FeBr₃

iron(III) oxide: Fe₂O₃

lead(IV) bromide: PbBr₄

lead(IV) oxide: PbO₂

I hope this helped you! Brainliest would be greatly appreciated.

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A 50.0 mL sample of 12.0 M HCl is diluted to 200 mL. What is true about the diluted solution?
kobusy [5.1K]

The concentration of the solution reduces and the number of moles of solute isn't affected.

Data;

  • V1 = 50mL
  • C1 = 12.0M
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<h3>Facts about the diluted solution</h3>

1. When the solution is diluted, the concentration changes and this time, the concentration reduces.

Using dilution formula

c_1 v_1 = c_2 v_2\\12 * 50 = c_2 * 200\\c_2 = \frac{600}{200} \\c_2 = 3M

The concentration of the solution reduces.

2. The number of moles remains the same.

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Learn more on concentration of a solution here;

brainly.com/question/2201903

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3 years ago
Plutonium-240 decays according to the function \[Q(t)=Q _{o}e ^{-kt}\] where Q represents the quantity remaining after t years a
marishachu [46]
To answer the question above, substitute the given values to the given equation,
                                   Q(t) = Q x e^-kt
  
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Solving for t gives t = 9,987.38 years or approximately equal to 9,990 years. Thus, the answer is letter C.












4 0
3 years ago
Read 2 more answers
I’ll give 5 stars and Brainliest plus this is 20 points lol
Daniel [21]

Answer:

I think is b

Explanation:

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