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3 years ago

Decide if each equation is true or false.

Mathematics

2 answers:

julia-pushkina [17]3 years ago

6 0

The third and fifth ones are false. Two negative numbers in the same equation make a positive not a negative

noname [10]3 years ago

5 0

True,false,false,true,true,false,true,false.

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Judy is a single woman, 25 years old. Her take home pay is $2314.92/month. She also earns $48 interest per month on her savings

Leni [432]

The monthly budget plan for Judy includes all of her income and expenses, the total balance is $ 2362.92 and she spends $ 1083.

<h3>What is the monthly budget?</h3>

A monthly budget is a personal spending plan that you use to track your monthly income and costs.

The given data in the problem is;

Home pay = $2314.92/month.

Interest earned = $48 / month

House rent = $825/month

EMI of student loan = $258/month

Total earning per month = $2314.92 + $48

Total earning per month = $ 2362.92

Amount she spends per month = $825/month + $258

Amount she spends per month = $ 1083

Hence, the total balance will be $ 2362.92 and she spend $ 1083.

To learn more about the monthly budget refer to:

brainly.com/question/570904

#SPJ1

3 0

2 years ago

640 rounded to the nearest tens

Reptile [31]

It is rounded to the nearest tens. You can only round when you have 1,9. Hope I helped

6 0

3 years ago

Read 2 more answers

Isaac keeps track of the amount of money in his savings certificate each month. He has accumulated the following data:

Dafna1 [17]

Answer:

d. The common ratio is 1.1

Step-by-step explanation:

To see if the data has a common ratio or common difference, we have to see if the division between them is equal(common ratio), or if the difference between them is equal(common difference).

In this case, since $60.5 - 55 \neq 55 - 50$ , it has a common ratio.

To find it, we divide consecutive terms. For example:

$\frac{55}{50} = 1.1$

So the correct answer is:

d. The common ratio is 1.1

3 0

3 years ago

Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0

Leokris [45]

Substitute $v(x)=-2x+y(x)$ , so that $\dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}$ . Then the ODE is equivalent to

$\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7$

which is separable as

$\dfrac{\mathrm dv}{v^2-9}=\mathrm dx$

Split the left side into partial fractions,

$\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)$

so that integrating both sides is trivial and we get

$\dfrac{\ln|v-3|-\ln|v+3|}6=x+C$

$\ln\left|\dfrac{v-3}{v+3}\right|=6x+C$

$\dfrac{v-3}{v+3}=Ce^{6x}$

$\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}$

$\dfrac6{v+3}=1-Ce^{6x}$

$v=\dfrac6{1-Ce^{6x}}-3$

$-2x+y=\dfrac6{1-Ce^{6x}}-3$

$y=2x+\dfrac6{1-Ce^{6x}}-3$

Given the initial condition $y(0)=0$ , we find

$0=\dfrac6{1-C}-3\implies C=-1$

so that the ODE has the particular solution,

$\boxed{y=2x+\dfrac6{1+e^{6x}}-3}$

5 0

3 years ago

If f(x) = x2 + x, find f(-3).<br> -12<br> 3<br> 6

ANEK [815]

Answer:

-9

Step-by-step explanation:

-3(2) + (-3)

-6 + (-3)

-9

4 0

2 years ago

Read 2 more answers