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scZoUnD [109]
3 years ago
11

Decide if each equation is true or false.

Mathematics
2 answers:
julia-pushkina [17]3 years ago
6 0
The third and fifth ones are false. Two negative numbers in the same equation make a positive not a negative
noname [10]3 years ago
5 0
True,false,false,true,true,false,true,false.
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Judy is a single woman, 25 years old. Her take home pay is $2314.92/month. She also earns $48 interest per month on her savings
Leni [432]

The monthly budget plan for Judy includes all of her income and expenses, the total balance is $ 2362.92 and she spends $ 1083.

<h3>What is the monthly budget?</h3>

A monthly budget is a personal spending plan that you use to track your monthly income and costs.

The given data in the problem is;

Home pay = $2314.92/month.

Interest earned = $48 / month

House rent = $825/month

EMI of student loan =  $258/month

Total earning per month = $2314.92 +  $48

Total earning per month = $ 2362.92

Amount she spends per month = $825/month + $258

Amount she spends per month = $ 1083

Hence, the total balance will be $ 2362.92 and she spend $ 1083.

To learn more about the monthly budget refer to:

brainly.com/question/570904

#SPJ1

3 0
2 years ago
640 rounded to the nearest tens
Reptile [31]

It is rounded to the nearest tens. You can only round when you have 1,9. Hope I helped

6 0
3 years ago
Read 2 more answers
Isaac keeps track of the amount of money in his savings certificate each month. He has accumulated the following data:
Dafna1 [17]

Answer:

d. The common ratio is 1.1

Step-by-step explanation:

To see if the data has a common ratio or common difference, we have to see if the division between them is equal(common ratio), or if the difference between them is equal(common difference).

In this case, since 60.5 - 55 \neq 55 - 50, it has a common ratio.

To find it, we divide consecutive terms. For example:

\frac{55}{50} = 1.1

So the correct answer is:

d. The common ratio is 1.1

3 0
3 years ago
Find the solution of the initial value problem<br><br> dy/dx=(-2x+y)^2-7 ,y(0)=0
Leokris [45]

Substitute v(x)=-2x+y(x), so that \dfrac{\mathrm dv}{\mathrm dx}=-2+\dfrac{\mathrm dy}{\mathrm dx}. Then the ODE is equivalent to

\dfrac{\mathrm dv}{\mathrm dx}+2=v^2-7

which is separable as

\dfrac{\mathrm dv}{v^2-9}=\mathrm dx

Split the left side into partial fractions,

\dfrac1{v^2-9}=\dfrac16\left(\dfrac1{v-3}-\dfrac1{v+3}\right)

so that integrating both sides is trivial and we get

\dfrac{\ln|v-3|-\ln|v+3|}6=x+C

\ln\left|\dfrac{v-3}{v+3}\right|=6x+C

\dfrac{v-3}{v+3}=Ce^{6x}

\dfrac{v+3-6}{v+3}=1-\dfrac6{v+3}=Ce^{6x}

\dfrac6{v+3}=1-Ce^{6x}

v=\dfrac6{1-Ce^{6x}}-3

-2x+y=\dfrac6{1-Ce^{6x}}-3

y=2x+\dfrac6{1-Ce^{6x}}-3

Given the initial condition y(0)=0, we find

0=\dfrac6{1-C}-3\implies C=-1

so that the ODE has the particular solution,

\boxed{y=2x+\dfrac6{1+e^{6x}}-3}

5 0
3 years ago
If f(x) = x2 + x, find f(-3).<br> -12<br> 3<br> 6
ANEK [815]

Answer:

-9

Step-by-step explanation:

-3(2) + (-3)

-6 + (-3)

-9

4 0
2 years ago
Read 2 more answers
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