According to Newton's 3rd law, there will be equal and opposite force on the astronaut which is -6048 N
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What does Newton's third law say ?</h3>
The law state that in every action, there will be equal and opposite reaction.
Given that a rocket takes off from Earth's surface, accelerating straight up at 69.2 m/s2. We are to calculate the normal force (in N) acting on an astronaut of mass 87.4 kg, including his space suit.
Let us first calculate the force involved in the acceleration of the rocket by using the formula
F = ma
Where mass m = 87.4 kg, acceleration a = 69.2 m/s2
Substitute the two parameters into the formula
F = 87.4 x 69.2
F = 6048.08 N
According to the Newton's 3rd law, there will be equal and opposite force on the astronaut.
Therefore, the normal force acting on the astronaut is -6048 N approximately
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Answer: 13.2 seconds.
Explanation: using equation of motion; S= ut +1/2at² where u = initial velocity=0
S= distance travelled
a = acceleration due gravity
t= time.
1 foot = 0.305m so,
S= 2860 feet =872.3m
S= ut+1/2 at²
872.3 = 0×t + 1/2×10 × t²
872.3 =0 + 5t²
T²= 872.3/5
T²= 174.46
Take the square root of T we then have;
t = 13.2 seconds to one decimal place.
Answer:
The probability of an incorrect report is found to be 0.03 or 3%.
Explanation:
We will get an incorrect report in both the cases of false alarm or missing excessive radiation. Since, both are mutually exclusive events. Therefore, the probability of both events to occur simultaneously will be 0. Thus, the probability of an incorrect report will be the sum of the probability of false alarm and the probability of a missing radiation.
P (False Alarm) = 0.02
P (Missing Radiation) = 0.01
P(Incorrect Report) = P (False Alarm) + P(Missing Radiation)
P (Incorrect Report) = 0.02 +0.01
P(Incorrect Report) = 0.03 = 3%
Given:
Mass(m)=75kg
Height (h) =100m
v(velocity)=60m/s
a(g)=9.8m/s^2(since it is a free falling object)
Now we know that
v=u+at
We know that
Potential energy=mgh
Where m is the mass
g is the acceleration due to gravity
h is the height above the ground
Substituting the above values we get
Potential energy=75 x 9.8 x 100
=73500N
Now kinetic energy =1/2mv^2
Where m is the mass
v is the velocity
Kinetic energy= 1/2 (75x60 x 60)
Kinetic energy=135000N
Now mechanical energy=
Kinetic energy+ Potential energy
Substituting the values in the above formula we get
Mechanical energy= 73500+135000
=208500N
