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IrinaVladis [17]
3 years ago
8

If you help me answer these questions you will get 23 points!

Physics
1 answer:
sashaice [31]3 years ago
8 0
1) kg
2) cylinder
3)Micro metre
4) millimeters
5)metres
6)
7)1100
8)0.5
9)5000
10)1500
11)10
12)20grams
13)50
14)micrometre
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A 0.50-kg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.9 m on a frictionless horizontal su
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Answer:

\boxed {\boxed {\sf 18 \ m/s}}

Explanation:

The ball is moving in a circle, so the force is centripetal.

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F_c= \frac{mv^2}r}

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85 \ kg*m/s^2 = \frac{0.5 \ kg *v^2}{1.9 \ m}

Isolate the variable v. First, multiply both sides by 1.9 meters.

(1.9 \ m)(85 \ kg*m/s^2) = \frac{0.5 \ kg *v^2}{1.9 \ m}*1.9 \ m

(1.9 \ m)(85 \ kg*m/s^2) = {0.5 \ kg *v^2}

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\frac {161.5 \ kg*m^2/s^2}{0.5 \ kg} = \frac{0.5 \ kg*v^2}{0.5 \ kg}

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\sqrt {323 \ m^2/s^2} =\sqrt{ v^2

\sqrt {323 \ m^2/s^2} =v

17.9722007556 \ m/s =v

The original measurements have 2 significant figures, so our answer must have the same.

For the number we found, 2 sig fig is the ones place. The 9 in the tenth place tells us to round the 7 to an 8.

18 \ m/s =v

The maximum speed is approximately <u>18 meters per second.</u>

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