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Georgia [21]
3 years ago
9

Carbon dioxide (CO2) fills a closed, rigid tank fitted with a paddle wheel, initially at 80°F, 30 lbf/in2, and a volume of 1.6 f

t3. The gas is stirred until its temperature is 500°F. During this process heat transfer from the gas to its surroundings occurs in an amount 2.6 Btu. Assume ideal gas behavior, but do not assume constant specific heats. Kinetic and potential energy effects can be ignored. Determine the mass of the carbon dioxide, in lb, and the work, in Btu.
Chemistry
1 answer:
solong [7]3 years ago
8 0

Answer:

The answer to this question can be given as:  

The initial pressure P= 30 lbf/in2

The initial temperature T1=80°F.

The initial volume=final volume V= 1.6 ft3.

Final  temperature T2=500°F

Heat transfer Q=-2.6 Btu.

pressure (P) (lbf/in2) change into lbf/ft2

P=30 lbf/in2=4320lbf/ft2.

Temperature (T1) °F change into °K

temperature T1=80°F=539.67 °K

Ideal gas formula:

M=PV/RT1.                   where T1=initial temperature.

M=4320*1.6/35.114*539.67.

M=0.364749 lb             Mass at Carbon dioxide (CO2).

DQ=DU+W            second law.

-2.6=MCV(T2-T1)+ W        

-2.6-(0.364749*1.6(500-80))=W

W=-27.111 b+u  am----> work done.

Explanation:

The explanation to this question can be given as:

Firstly we write the equation that is given in the question like, pressure, volume, gas constant, temperature. Then we covert the pressure and temperature into there possible values. Then We apply the formula of Ideal gas that is  M=PV/RT1. where M is  the mass, P is the pressure , V is the volume , R is the gas constant (0.08206 L·atm·K−1·mol−1)  and T1 is the initial temperature. Then we use the second formula that is DQ=DU+W. Where DQ= Heat transfer, DU=MCV(T2-T1)and W= work. It is used for finding work.

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From the question,

Given: R = 40 atoms, R' = 5 atoms

Substitute these values into equation 1

2^{n'} = 40/5

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Answer:

2 litres of pure alcohol will be added to make the overall concentration of 9 litres of mixture as 30%.

Explanation:

Suppose x is the number of litres added to the 10% mixture than the quantity of new mixture is given as below

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Also the quantity of alcohol is given as

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Now the equation is as

                                  q_{old}+q_{added}=q_{new}\\0.7+x=0.3(7+x)\\0.7+x=2.1+0.3x\\x-0.3x=2.1-0.7\\0.7x=1.4\\x=2 \, litres

So 2 litres of pure alcohol will be added to make the overall concentration of 9 litres of mixture as 30%.

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In a certain city, electricity costs $0.15 per kW·h. What is the annual cost for electricity to power a lamp-post for 6.00 hours
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1 W=\frac{1}{1000}kW

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100 W =\frac{100}{1000}kW=0.1 kW

The bulb is used for 6 hours per day for a year, in 1 year there are 365 days thus, total hours will be:

t=6\times 365=2190 h

Electricity used will depend on power and number of hours as follows:

E=P\times t=0.1 kW\times 2190 h=219 kW.h

The cost of electricity is $0.15 per kW.h thus, cost of electricity for 219 kW.h will be:

Cost=\$ (219\times 0.15)=\$ 32.85

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(b) Power of bulb is 25 W, converting this into kW.

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Thus,

100 W =\frac{25}{1000}kW=0.025 kW

The bulb is used for 6 hours per day for a year, in 1 year there are 365 days thus, total hours will be:

t=6\times 365=2190 h

Electricity used will depend on power and number of hours as follows:

E=P\times t=0.025 kW\times 2190 h=54.75 kW.h

The cost of electricity is $0.15 per kW.h thus, cost of electricity for 54.75 kW.h will be:

Cost=\$ (54.75\times 0.15)=\$ 8.21

Therefore, annual cost of fluorescent bulb is \$ 8.21.

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