actual yield of ethanol = 305.0g
molar mass of sucrose = 342g
molar mass of ethanol =46g
mass of sucrose = 665g
mole of sucrose = mass / molar mass = 665/342
mole of sucrose =1.9 mole
sucrose : C2H5OH
1 : 4
1.9 : 1.9x4 =7.6 mole of C2H5OH are formed
mass (therotical yield ) of C2H5OH= mole x mass
mass (therotical yield ) of C2H5OH= 7.6 x 46 = 349.6g
percent yields of ethanol = actual /therotical x100
=305/349.6x100 = 87.24 %
Answer: 0.6159872299002939 or 0.61 or 0.615 I think please don't get mad if I got this wrong
Answer:
5.77 s
Explanation:
From the question,
The total time travelled by the projectile = Time of flight (T)
T = 2usinθ/g............ Equation 1
Where T = Time of Flight of the projectile, u = Initial velocity, θ = Angle of projection to the horizontal, g = acceleration due to gravity
Given: u = 40 m/s, θ = 45°
Constant: g = 9.8 m/s²
Substitute these values into equation 1
T = 2(40)sin(45°)/9.8
T = 80sin(45°)/9.8
T = 80×0.7071/9.8
T = 5.77 s
Hi! the question has some missing portion. The complete question is "T(K) means the temperature in the unit Kelvin. T(C) means the temperature in Celsius. If T(K) = T(C) + 273, and the current temperature is -27 C, what is the current temperature in kelvin?"
Answer: The current temperature is 246 K.
Explanation:
Kelvin is the SI unit of temperature which is symbolized as K. It is often called the absolute temperature. The lowest possible temperature in a Kelvin scale is "0". There exists no temperature beyond "0 K".
The mathematical relation between the temperature in the Kelvin scale to the temperature in the degree Celcius scale is given as:
......................... (1)
The current temperature in the degree Celcius scale is
Substituting the above value into equation-(1), we get:
Answer:
555 g of CaCl₂
Explanation:
We'll begin by writing the balanced equation for the reaction. This is given below:
Ca + Cl₂ —> CaCl₂
From the balanced equation above,
1 mole of Cl₂ reacted to produce 1 mole of CaCl₂.
Next, we shall determine the number of mole of CaCl₂ produced by the reaction of 5 moles of Cl₂. This can be obtained as follow:
From the balanced equation above,
1 mole of Cl₂ reacted to produce 1 mole CaCl₂.
Therefore, 5 moles of Cl₂ will also react to produce 5 moles of CaCl₂.
Thus, 5 moles of CaCl₂ were obtained from the reaction.
Finally, we shall determine the mass of 5 moles of CaCl₂. This can be obtained as follow:
Mole of CaCl₂ = 5 moles
Molar mass of CaCl₂ = 40 + (35.5×2)
= 40 + 71
= 111 g/mol
Mass of CaCl₂ =?
Mass = mole × molar mass
Mass of CaCl₂ = 5 × 111
Mass of CaCl₂ = 555 g
Therefore, 555 g of CaCl₂ were obtained from the reaction.