Answer:
First, the number of ammonium sulfide molecules should be calculated:
N = NA × n,
where NA - the Avogadro number, n - number of moles.
N (ammonium sulfide) = 6.022 × 1023 × 8.5 mol = 51.187 × 1023.
The moelcular formula of ammonium sulfide is (NH4)2S. It means that each molecule contains 8 hydrogen atoms.
As a result, 8.5 mol of (NH4)2S contain:
51.187 × 1023 × 8 = 41 × 1024 hydrogen atoms.
Answer: 41 × 1024 hydrogen atoms
H₂ + CO₂ ⇄ CO + H₂O
1 mol H₂ - 1 mol H₂O
x mol H₂ - 30.6 mol H₂O
x=30.6*1/1=30.6 mol (<span>theoretically)</span>
Answer:
A
Explanation:
Chemical compound
Lead(II) chloride is an inorganic compound which is a white solid under ambient conditions. It is poorly soluble in water. Lead(II) chloride is one of the most important lead-based reagents. It also occurs naturally in the form of the mineral cotunnite.
Answer:
0.497 moles/L
Explanation:
The reaction that takes place is:
- C₃H₆O₃ + NaOH → C₃H₅ONa + H₂O
First we c<u>alculate the moles of lactic acid in 0,821 g</u>, using its molar mass:
- 0,821 g ÷ 90 g/mol = 9,122x10⁻³mol lactic acid
<em>One mole of lactic acid reacts with one mole of sodium hydroxide</em> (it is a monoprotic acid), so in 18,34 mL of NaOH solution there are 9,122x10⁻³moles of NaOH:
- 18.34 mL ÷ 1000 = 0,01834 L
- 9,122x10⁻³mol ÷ 0,01834 L = 0.497 moles/L
Answer:
B. NaBr
D. KOH
Explanation:
Below is the solubility rules given for you knowledge.
Salts of
- Group 1 elements are soluble(
) - Ammonium ion is soluble (
) - The nitrate are generally soluble(
- of Cl- , Br- , and I- are soluble, except Ag+ , Pb+2, and (Hg2)+2
- most sulfate are soluble, except Ba+2, Ca+2,Pb+2, Ag+, Sr+2.
- most hydroxide salts are only slightly soluble, except NH+4, Li+, Na+, K+
- Most carbonates are insoluble (CO3 2-) Except group 1 and NH+4
- most phosphate are insoluble except group 1 and NH+4
so using the rules above
NaBr , KOH are soluble, Pb(OH)2 is slightly soluble and AgCl is not soluble.
