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4 years ago

El numero de moles en 70 gramos de HF

Chemistry

2 answers:

Katarina [22]4 years ago

8 0

7 moles, because there are about 10 grams in HF and 70 grams of HF/10 grams of HF= 7 moles

saveliy_v [14]4 years ago

7 0

Answer:

enviornmental health perspectives

Explanation:

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At 25°C, K = 0.090 for the following reaction. H2O(g) + Cl2O(g) equilibrium reaction arrow 2 HOCl(g) Calculate the concentration

wlad13 [49]

Answer:

[HOCl] = 0.00909 mol/liter

[H₂O] = 0.03901 mol/liter

[Cl₂O] = 0.02351 mol/liter

Explanation:

1. Chemical reaction:

$H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)$

2. Initial concentrations:

i) 1.3 g H₂O

Number of moles = 1.3g / (18.015g/mol) = 0.07216 mol

Molarity, M = 0.07216 mol / 1.5 liter = 0.0481 mol/liter

ii) 2.2 g Cl₂O

Number of moles = 2.2 g/ (67.45 g/mol) = 0.0326 mol

Molarity = 0.0326mol / 1.5 liter = 0.0217 mol/liter

3. ICE (Initial, Change, Equilibrium) table

$H_2O(g)+Cl_2O(g)\rightleftharpoons 2 HOCl(g)$

I 0.0481 0.0326 0

C -x -x +x

E 0.0481-x 0.0326-x x

4. Equilibrium expression

$K_c=\dfrac{[HOCl]^2}{[H_2O].[Cl_2O]}$

$0.09=\dfrac{x^2}{(0.0481-x)(0.0326-x)}$

5. Solve:

$x^2=0.09(x-0.0481)(x-0.0326)\\\\0.91x^2+0.007263x-0.000141125=0$

Use the quadatic formula:

$x=\dfrac{-0.007263\pm \sqrt{(0.007263)^2-4(0.91)(-0.000141125)}}{2(0.91)}$

The positive result is x = 0.00909

Thus the concentrations are:

[HOCl] = 0.00909 mol/liter

[H₂O] = 0.0481 - 0.00909 = 0.03901 mol/liter

[Cl₂O] = 0.0326 - 0.00909 = 0.02351 mol/liter

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3 years ago

All moving objects have kinetic energy. True False

aivan3 [116]

Answer:

true

.......................

4 0

3 years ago

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What willl happen if we nuke the sun some how

iogann1982 [59]

Answer:

The sun'll likely absorb the radiation if it is close enough (Which it will never be)

Explanation:

4 0

3 years ago

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A gas is under a pressure of 760torr and occupies volume of 525cm3. If the pressure is doubled, what volume would gas now occupy

german

262. 5cm3.

using the Boyles law formula. p1v1=p2v2

P1=760torr.

v1=525cm³

p2=760×2=1520torr.

v2=?

p1v1=p2v2

760×525=1520×v2

v2=[ 760×525]÷1520

v2= 262.5cm³

when the pressure increases, the volume decreases.

5 0

3 years ago

How many grams are in 4.23 x 1024 atoms of He?

Dmitry [639]

Answer:

28.11g

Explanation:

Step 1:

Background understanding:

From Avogadro's hypothesis, 1 mole of any substance contains 6.02x10^23 atoms. This also indicates that 1 mole of helium (He) contains 6.02x10^23 atoms.

1 mole of He = 4g

Step 2:

Determination of the mass of He that contain 4.23x10^24 atoms. This is illustrated below:

4g of He contains 6.02x10^23 atoms.

Therefore Xg of He will contain 4.23x10^24 atoms i.e

Xg of He = (4x4.23x10^24)/6.02x10^23

Xg of He = 28.11g

Therefore, 28.11g of He contains 4.23x10^24 atoms

7 0

3 years ago