Answer:
Yes. Towards the center. 8210 N.
Explanation:
Let's first investigate the free-body diagram of the car. The weight of the car has two components: x-direction: towards the center of the curve and y-direction: towards the ground. Note that the ground is not perpendicular to the surface of the Earth is inclined 16 degrees.
In order to find whether the car slides off the road, we should use Newton's Second Law in the direction of x: F = ma.
The net force is equal to 
Note that 95 km/h is equal to 26.3 m/s.
This is the centripetal force and equal to the x-component of the applied force.
As can be seen from above, the two forces are not equal to each other. This means that a friction force is needed towards the center of the curve.
The amount of the friction force should be 
Qualitatively, on a banked curve, a car is thrown off the road if it is moving fast. However, if the road has enough friction, then the car stays on the road and move safely. Since the car intends to slide off the road, then the static friction between the tires and the road must be towards the center in order to keep the car in the road.
An object with a velocity (v) of 9 m/s and a linear momentum (p) of 72 kg.m/s, has a mass (m) of 8 kg.
<h3>What is momentum?</h3>
In Newtonian mechanics, linear momentum, or simply momentum, is the product of the mass and velocity of an object.
It is a vector quantity, possessing a magnitude and a direction.
The mathematical expression for momentum is:
p = m . v
where,
- p is the linear momentum of the object.
- m is the mass of the object.
- v is the velocity of the object.
An object has a velocity (v) of 9 m/s and its linear momentum (p) is 72 kg.m/s. We will use the definition of linear momentum to calculate the mass of the object.
p = m . v
m = p / v
m = (72 kg.m/s) / (9 m/s) = 8 kg
An object with a velocity (v) of 9 m/s and a linear momentum (p) of 72 kg.m/s, has a mass (m) of 8 kg.
Learn more about linear momentum here: brainly.com/question/7538238
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answer is 36
because the formulae of momentum is
mass×velocity
Answer:
Though there is no chart on my screen, I can give you the correct information to solve the question without knowing what it looks like. Assuming that this track has slopes and or ramps of any kind, the place where it would have the most potential energy would be at the highest point of this ramp, or and the highest point on the track. This would also mean that it would fall the farthest. The highest kinetic energy would be at the lowest part of the ramp, after its used the slope to its full ability. But this would also be before it hits flat ground, or starts going up another ramp. This would be the point where it would be going its fastest.
Explanation:
Answer:
<em>The force exerted by each string is 25 N</em>
Explanation:
<u>Net Force</u>
The net force is the vector sum of forces acting on a body. The net force is a single force that represents the effect of the original forces on the body's motion. It gives the particle the same acceleration as all those actual forces together as described by Newton's second law of motion.
The picture described in the problem is hanging at rest supported by two vertical strings. This means that the net force acting on it is zero.
Assume the magnitude of each of these equal forces is F, and the picture has a weight of W=50 N, thus the net force is:
F + F - W
The positive signs indicate an upwards direction and the negative sign means a downwards direction. Since the net force is zero:
F + F - W = 0
2F = W
F = W/2 = 50 N/2
F = 25 N
The force exerted by each string is 25 N
