HEEEEELP!!!!!! :((( help me with this exercise.
1 answer:
Answer:
- See the graph attached with the vectors.
Explanation:
The exercise is to draw the corresponding vectors:
Every one is the multiplication of a scalar by a vector.
The result of multiplying a scalar by a vector is a vector with the same direction of the original vector enlarged in a factor equal to the scalar magntitude.
Thus, in a graph the resulting vector is represented with a parallel arrow and pointing in the same direction as the original vector but with a length equal to the original length multiplied by the magnitude of the scalar.
For instance, the vector is represented with an arrow in the same direction of
and with twice its length.
The figure attached contains the five requested vectors using the procedure explained above.
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Answer:
The net force acting on this object is 180.89 N.
Explanation:
Given that,
Mass = 3.00 kg
Coordinate of position of
Coordinate of position of
Time = 2.00 s
We need to calculate the acceleration
For x coordinates
On differentiate w.r.to t
On differentiate again w.r.to t
The acceleration in x axis at 2 sec
For y coordinates
On differentiate w.r.to t
On differentiate again w.r.to t
The acceleration in y axis at 2 sec
The acceleration is
We need to calculate the net force
The magnitude of the force
Hence, The net force acting on this object is 180.89 N.