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Papessa [141]
3 years ago
15

What are the two reasons why metals are good conductors of electricity?​

Physics
2 answers:
Radda [10]3 years ago
4 0

Answer:

Explanation:

Metals are good conductor of electricity because they have very large number of free valance electrons whereas glass has no free electrons to conduct electricity. So metals good conductor whereas glass is a bad conductor of electricity.

kenny6666 [7]3 years ago
3 0

Answer:

Metals are excellent conductors because the atoms in a metal form a matrix through which their outer electrons can move freely.

Explanation:

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Which two factors affect the amount of thermal energy an object has?
leonid [27]

Answer:

B

Explanation:

When the average kinetic energy increases, the thermal energy increases

6 0
3 years ago
Read 2 more answers
List of most launched orbital launch vehicles
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4 0
3 years ago
Cart A of inertia m has attached to its front end a device that explodes when it hits anything, releasing a quantity of energy E
Leviafan [203]
We need to write down momentum and energy conservation laws, this will give us a system of equation that we can solve to get our final answer. On the right-hand side, I will write term after the collision and on the left-hand side, I will write terms before the collision.
Let's start with energy conservation law:
\frac{mv^2}{2}+\frac{2mv^2}{2}+0.75E=\frac{mv_{A}^2}{2}+\frac{2mv_{B}^2}{2}
\frac{3mv^2}{2}+0.75E=\frac{mv_{A}^2}{2}+mv_{B}^2
This equation tells us that kinetic energy of two carts before the collision and 3 quarters of explosion energy is beign transfered to kinetic energy of the cart after the collision.
Let's write down momentum conservation law:
mv+2mv=mv_A+2mv_B\\ 3mv=mv_A+2mv_B\\
Because both carts have the same mass we can cancel those out:
3v=v_A+2v_B
Now we have our system of equation that we have to solve:
\frac{3mv^2}{2}+0.75E=\frac{mv_{A}^2}{2}+mv_{B}^2\\ 3v=v_A+2v_B
Part A
We need to solve our system for v_a. We will solve second equation for v_b and then plug that in the first equation.
3v=v_A+2v_B\\ 3v-v_A=2v_B\\ v_B=\frac{3v-v_A}{2}
Now we have to plug this in the first equation:
\frac{3mv^2}{2}+0.75E=\frac{mv_{A}^2}{2}+mv_{B}^2\\v_B=\frac{3v-v_A}{2}\\
We will multiply the first equation with 2 and divide by m:
3v^2+\frac{3E}{2m}=v_{A}^2}+2v_{B}^2\\v_B=\frac{3v-v_A}{2}\\
Now we plug in the second equation into first one:
3v^2+\frac{3E}{2m}=v_{A}^2}+2v_{B}^2\\ 3v^2+\frac{3E}{2m}=v_{A}^2}+2\frac{(3v-v_A)^2}{4}\\ 3v^2+\frac{3E}{2m}=v_{A}^2}+\frac{9v^2-6v\cdot v_A+v_{A}^2}{2} /\cdot 2\\ 6v^2+\frac{3E}{m}=2v_{A}^2+9v^2-6v\cdot v_A+v_{A}^2}\\ 3v_A^2-6v\cdot v_a+3(v^2-\frac{E}{m})=0/\cdot\frac{1}{3}\\ v_A^2-3v\cdot v_A+ (v^2-\frac{E}{m})=0
We end up with quadratic equation that we have to solve, I won't solve it by hand. 
Coefficients are:
a=1\\&#10;b=-6v\\&#10;c=v^2-\frac{E}{m}
Solutions are:
v_A=\frac{3v+\sqrt{5v^2+\frac{4E}{m}}}{2},\:v_A=\frac{3v-\sqrt{5v^2+\frac{4E}{m}}}{2}
Part B
We do the same thing here, but we must express v_a from momentum equation:
3v=v_A+2v_B\\&#10;v_A=3v-2v_B
Now we plug this into our energy conservation equation:
3v^2+\frac{3E}{2m}=v_{A}^2}+2v_{B}^2\\v_A={3v-v_B}\\&#10;3v^2+\frac{3E}{2m}=(3v-v_B)^2+2v_B^2\\&#10;3v^2+\frac{3E}{2m}=9v^2-6v\cdot v_B+v_B^2+2v_B^2\\&#10;3v^2+\frac{3E}{2m}=3v_B^2-6v\cdot v_B+9v^2\\&#10;3v_B^2-6v\cdot v_B+9v^2-3v^2-\frac{3E}{2m}=0\\&#10;3v_B^2-6v\cdot v_B+(6v^2-\frac{3E}{2m})=0&#10;
Again we end up with quadratic equation. Coefficients are:
a=3\\&#10;b=-6v\\&#10;c=6v^2-\frac{3E}{2m}
Solutions are:
v_B=\frac{6v+\sqrt{-36v^2+\frac{18E}{m}}}{6},\:v_B=\frac{6v-\sqrt{-36v^2+\frac{18E}{m}}}{6}



8 0
3 years ago
Total resistance across any branch of a circuit can be found by analyzing whether the branch is connected in
atroni [7]

Answer: A.

series or parallel

Explanation:

Total resistance across any branch of a circuit can be found by analyzing whether the branch is connected in series or parallel.

The resistors are connected either in series or parallel. Therefore, the resistance of resistors across a circle can be calculated in series and parallel.

7 0
3 years ago
A truck travels to and from a stone quarry that is located 2.5km to the east.
Harrizon [31]

Answer:

Distance is 5.0 km and displacement is 0 km.

Explanation:

The diagram is shown below.

Distance is the total length that the truck covers along the complete journey. The truck moves from a stone quarry covering a length of 2.5 km and then again come back to the same point and thus covering another 2.5 km. Therefore, the total length covered by the truck is the sum of forward and backward paths which is equal to 5.0 km.

Now, displacement depends only on the initial and final position. It is given as the difference of final position and initial position. So, the truck starts from stone quarry and returns back to the same position. So, the initial position and final position is same. Therefore, the difference is 0 and hence displacement is zero.

5 0
3 years ago
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