Answer:
Continuously changing magnetic field of the Sun
Explanation:
The Sun is made up of plasma and is not solid like our planet. When it rotates the whole of the Sun doesn't rotate with same speed. The equatorial part completes the rotation in just 25 days whereas the poles do it in 35 days. Due to this the magnetic field lines entangle and reorganize them regularly.
The places where the field line exit and enter the surface of the Sun, temperature drops by around 1000 K thus these spots appear black in color and are known as Sun spots.
The magnetic field is not permanent as it will keep changing due to differential rotation. This will result in the change in the no. of location of Sun spots.
If we track the no. of sunspots visible with respect to years we will notice that they follow a cycle of 10.6 years. This is known as Solar cycle in which there comes a solar minima when we see very few sunspots. When it is solar maxima we can see more than 100 sunspots.
Answer:
The magnitude of the angular momentum of the Mars in a circular orbit around the sun is
Explanation:
Given that,
Mass of mars
Radius
Orbit radius
Time period = 687 days
We need to calculate the magnitude of the angular momentum of the mars
Using formula of angular momentum
Here,
Where,
L = angular momentum
I = moment of inertia
r = radius
=angular speed
Put the value into the formula
Hence, The magnitude of the angular momentum of the Mars in a circular orbit around the sun is
Answer:
.864 M
Explanation:
For first order decomposition,
rate constant k = 1/t x ln a / (a - x )
given , a = 1.33 M , t = 644 s , k = 6.7 x 10⁻⁴ , a - x = ? = b( let )
6.7 x 10 ⁻⁴ = 1/644 x ln 1.33/b
ln 1.33/b = 6.7 x 10⁻⁴ x 644 = .4315
1.33 / b = e⁰ ⁴³¹⁵ = 1.5395
b = 1.33 / 1.5395 = .864 M.
, density is how compact an object is. Put another way, density is the mass of an object divided by its volume.
Answer:
5×10¯⁴ m².
Explanation:
From the question given above, the following data were obtained:
Pressure (P) = 200 N/m²
Weight = Force (F) = 0.1 N
Area (A) =?
Pressure, force and area are related by the following equation:
Pressure (P) = Force (F) / Area (A)
P = F / A
With the above formula, we can obtain the area of the coin as follow:
Pressure (P) = 200 N/m²
Weight = Force (F) = 0.1 N
Area (A) =?
P = F / A
200 = 0.1 / A
Cross multiply
200 × A = 0.1
Divide both side by 200
A = 0.1 / 200
A = 5×10¯⁴ m²
Thus, the area of the coin is 5×10¯⁴ m².