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3 years ago

9

Find the product. (-5a ^2)^3 · a^5

1 answer:

GrogVix [38]3 years ago

4 0

Answer:

<u><em>−125a^(11)</em></u>

Step-by-step explanation:

<u><em>(−5a^(2)3a^(5) Then you solve</em></u>

<u><em>=−125a^(11)</em></u>

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In a recent survey of 1,000 randomly selected registered voters in the town of Armstrong, 803

labwork [276]

Answer:

12,922

Step-by-step explanation:

estimate = 16,092 * 803/1,000 = 12,922

6 0

3 years ago

Can u help me please better picture

gladu [14]

Hi, there.

For this question, we can apply the Pythagorean theorem $a^2 + b^2 = c^2$ .

I'm sure you've seen this equation before, and they kind of tried to trip you up with this problem. Trust me, it's easier than it looks. Let's break it down.

Lengths a and b both have the value of 48, which means that the value s in $\sqrt{2s^2}$ is 48, because the length of the hypotenuse is the same as the length and height squared multiplied by 2.

Plug in the value for c: $a^2 + b^2 = (\sqrt{2s^2})^2$

Plug in the value for s:

$(\sqrt{2(48^2)})^2$

Do the innermost exponents first:

$(\sqrt{2(2304)})^2$

The square root symbol and the power of 2 cancel each other out, so we are left with:

s = $2(2304)$ , so the hypotenuse is 4608 inches.

4 0

3 years ago

ALL HELP/ANSWER IS GREATLY APPRECIATED

Gnesinka [82]

Answer:

B i think!

Step-by-step explanation:

6 0

3 years ago

A computer and printer cost a total of $1212. The cost of the computer is two times the cost of the printer. Find the cost of ea

leva [86]

Answer:

printer 404 computer 808

Step-by-step explanation:

let the price of computer be c and printer be p

c+p=1212

c=2p

2p+p=1212

3p=1212

p=1212/3 =404

c=2p=2x404=808

4 0

2 years ago

orest fire covers 2008 acres at time t equals 0. The fire is growing at a rate of 8 StartRoot t EndRoot acres per hour, where t

AveGali [126]

Answer: There are 2635 acres covered 24 hours later.

Step-by-step explanation:

Since we have given that

At time t = 0, number of acres forest fire covers = 2008 acres

We first consider the equation:

$A=\int\limits^t_0 {8\sqrt{t}} \, dt\\\\A=8\dfrac{t^{\frac{3}{2}}}{\frac{3}{2}}+C\\\\A=\dfrac{16}{3}t^{\frac{3}{2}}+C$

At t=0, A= 2008

So, it becomes,

$2008=C$

So, now it becomes,

$A=\dfrac{16}{3}t^{\frac{3}{2}}+2008\\\\At\ t=24,\\\\A=\dfrac{16}{3}(24)^{\frac{3}{2}}+2008\\\\A=2635.06$

Hence, there are 2635 acres covered 24 hours later.

6 0

3 years ago