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AnnZ [28]
3 years ago
8

Mixing an acid and a base (of the same strength and in equal amounts) will result in

Chemistry
2 answers:
Sedbober [7]3 years ago
7 0
 <span>In my opinion, it is a rotten question, phrased as it is. It all depends on how much acid and how much base. It also depends on the type of acid (sulfuric acid reacts differently than hydrochloric - sulfuric has two atoms of hydrogen compared to hydrochloric which has one atom of hydrogen per molecule). It also can depend on the concentration - for example, if you're mixing a one molar solution of acid with a two molar solution of base, and on how much you are mixing - if you are mixing one liter of base with one liter of acid, or whatever. Your instructor needs to establish these things in order to make it a question you can actually answer. 

But, your instructor probably means what happens if you add the same amount of an acid and a base together, and they have the same strength. Ideally, if you mix the same amounts of an acid and a base, and the acid has one atom of hydrogen, then you would get water plus a salt, which would have a neutral pH. 

For example, HCl + NaOH, mixed in the same amounts and at the same concentrations would give you HOH (or water) plus NaCl (which is actually table salt). All acids and bases that are mixed in these equal concentrations always give you water plus a salt (although not always table salt - just what is chemically known as a "salt).</span>
Mnenie [13.5K]3 years ago
4 0

Answer: neutralization

Explanation:

Mixing an acid and a base (of the same strength and in equal amounts) will result in neutralization.

Neutralization is defined as the mixing of acid and base to produce salt and water. Since acid has high concentration, it can only be neutralized by the effect of base of equal strength to produce water (water is a compound of pH of 7).

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3 years ago
Calcium oxide or quicklime (CaO) is used in steelmaking, cement manufacture, and pollution control. It is prepared by the therma
Elena-2011 [213]

Answer:

The yearly release of CO_2 into the atmosphere is 6.73\times 10^{10} kg.

Explanation:

CaCO_3(s)\rightarrow CaO(s) + CO_2(g)

Annual production of CaO = 8.6\times 10^{10} kg=8.6\times 10^{13} g

Moles of CaO :

\frac{8.6\times 10^{13} g}{56 g/mol}=1.53\times 10^{12} moles

According to reaction, 1 mole of CaO is produced along with 1 mole of carbon-dioxide.

Then along with  1.53\times 10^{12} moles of CaO moles of carbon-dioxide moles produced will be:

\frac{1}{1}\times 1.53\times 10^{12} moles=1.53\times 10^{12} moles of carbon-dioxide

Mass of 1.53\times 10^{12} moles of carbon-dioxide:

1.53\times 10^{12}mol\times 44 g/mol=6.73\times 10^{13} g =6.73\times 10^{10} kg

The yearly release of CO_2 into the atmosphere is 6.73\times 10^{10} kg.

6 0
3 years ago
What is the oxidation state of cr in CrPO4 and Cr3(PO4)2?
soldi70 [24.7K]

Answer:

Explanation:

Oxidation state of Cr in CrPO₄

As a general rule, the algebraic sum of all the oxidation numbers of all atoms in a neutral compound is zero.

The compound above is in its neutral state and we sum all the oxidation numbers and equate to zero:

The oxidation number of P is -2

                                           O is -2

Let the oxidation number of Cr be x:

                              x + (-2) + 4(-2) = 0

                              x -2-8 = 0

                               x -10 = 0

                                x = +10

For Cr in Cr₃(PO₄)₂

         Using the same rule:

        2(x) + 2[-2 + 4(-2)] = 0

           2x + 2(-2-8) = 0

            2x -20 = 0

                x = +10

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3 years ago
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xxMikexx [17]

Answer:

B) The term "inert" was dropped because it no longer described all the group 8A elements.

Explanation:

Inert elements in chemistry simply refers to elements that are chemically inactive and are not expected to form any compounds. this is the general belief for the group 8 elements as they all have complete duplet/octet configurations (and ideally, they ought to be very stable with no tendency to form compounds by participating in the loss and gain of electrons). However the discovery of compounds like xenon tetrafluoride (XeF4) proved this to be wrong.

Again, the reason the term - inert gses was droppedis beacause this term is not strictly accurate because several of them do take part in chemical reactions.

After dropping the term - Inert gases, they are now referred to as noble gases.

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B.There are long underwater mountain chains

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