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tatuchka [14]
1 year ago
6

In the reaction H₂ + I₂ --> 2HI, what is the oxidation number of the hydrogen in the HI reactant? (2 pts)

Chemistry
1 answer:
brilliants [131]1 year ago
6 0

The oxidation number of hydrogen in HI will be 1.

The integer allocated to each element in a chemical combination would be the simplest definition of the oxidation number. The variety of electrons that atoms in such a molecule could share, lose or gain during forming chemical connections involving other atoms of such a specific item would be referred as the oxidation number.

HI = 0...(i)

The oxidation number of iodine is -1

Put the value of oxidation number of iodine in equation (i),

HI = 0

H × (-1) =0

H = 1

Therefore, the oxidation number of hydrogen in HI will be 1.

To know more about oxidation number.

brainly.com/question/29267461

#SPJ1

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An automobile is driving uphill. Which form of energy is not involved in this process?
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7 0
4 years ago
A solution of nitrous acid and potassium nitrite acts as a buffer due to reactions that occur within the solution when a strong
Ghella [55]

Answer:

a. NO₂⁻ + H⁺ → HNO₂

b. HNO₂ + OH⁻ → NO₂⁻ + H₂O

Explanation:

A buffer is defined as an aqueous mixture of a weak acid and its conjugate base or vice versa.

The buffer of the problem is HNO₂/NO₂⁻ <em>where nitrous acid is the weak acid and NO₂⁻ is its conjugate base.</em>

a. When a acid is added to a buffer as the buffer of the problem, the conjugate base will react with the acid, to produce the weak acid, thus:

NO₂⁻ + HCl → HNO₂ + Cl⁻

Ionic equation is:

NO₂⁻ + H⁺ + Cl⁻ → HNO₂ + Cl⁻

In the net ionic equation, you avoid the ions that don't react, that is:

<h3>NO₂⁻ + H⁺ → HNO₂</h3>

b. In the same way, the weak acid will react with the strong acid producing water and the conjugate base, thus:

HNO₂ + NaOH → NO₂⁻ + H₂O + Na⁺

The ionic equation is:

HNO₂ + Na⁺ + OH⁻ → NO₂⁻ + H₂O + Na⁺

And the net ionic equation is:

<h3>HNO₂ + OH⁻ → NO₂⁻ + H₂O</h3>

5 0
3 years ago
7. Lli(s) + N₂(g) → 2 Liz Ncs)
timurjin [86]

The number of mole of lithium, Li needed for the reaction is 3.2 moles (Option D)

<h3>Balanced equation </h3>

4Li + N₂(g) → 2Li₂N

From the balanced equation above,

2 moles of Li₂N were obtained from 4 moles of Li

<h3>How to determine the mole of lithium needed </h3>

From the balanced equation above,

2 moles of Li₂N were obtained from 4 moles of Li

Therefore,

1.6 moles of Li₂N will be obtained from = (1.6 × 4) / 2 = 3.2 moles of Li

Thus, 3.2 moles of Li are needed for the reaction

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