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tekilochka [14]
3 years ago
15

I need a squared number thats NOT even

Mathematics
2 answers:
iragen [17]3 years ago
7 0

Answer:

As all even square numbers are divisible by 4, the even numbers of the form 4n + 2 are not square numbers. As all odd square numbers are of the form 4n + 1, the odd numbers of the form 4n + 3 are not square numbers.

Wewaii [24]3 years ago
7 0

Answer:

9

Step-by-step explanation:

9 is a square number, since it can be written as 3 × 3.

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The answer would be A
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Let f(x) be a quadratic polynomial such that f(-4) = -22, f(-1)=2, and f(2)=-1. Let g(x)=f(x)^16. Find the sum of the coefficien
tamaranim1 [39]

Answer:

-2

Step-by-step explanation:

5 0
3 years ago
I need help on two questions!
Inessa05 [86]

1) Answer: \frac{x^{2}}{100} +\frac{y^{2}}{4} = 1

<u>Explanation:</u>

The equation of an ellipse is: \frac{(x-h)^{2}}{a^{2}} +\frac{(y-k)^{2}}{b^{2}} = 1 ; where (h, k) is the center, "a" is the x-radius, and "b" is the y-radius.

               Center                        Radius

x-axis:   (10 + -10)/2 = 0            10 - 0 = 10

  •       h = 0                             a = 10

y-axis:   (2 + -2)/2  = 0               2 - 0 = 2

  •       k = 0                             b = 2

Now, input the values into the equation:

\frac{(x-0)^{2}}{10^{2}} +\frac{(y-0)^{2}}{2^{2}} = 1

\frac{x^{2}}{100} +\frac{y^{2}}{4} = 1

************************************************************************

2) Answer: \frac{x^{2}}{1} +\frac{(y+2)^{2}}{4} = 1

<u>Explanation:</u>

Vertices are: (0, 1) and (0, -5) ------> x-values are the same, y = 1, -5

Covertices are: (-1, -2) and (1, -2) ----> y-values are the same, x = -1, 1


               Center                        Radius

x-axis:   (-1 + 1)/2 = 0                  1 - 0 = 1

  •       h = 0                             a = 1

y-axis:   (1 + -5)/2  = -2               1 - (-2) = 3

  •       k = -2                             b = 3

Now, input the values into the equation:

\frac{(x-h)^{2}}{a^{2}} +\frac{(y-k)^{2}}{b^{2}} = 1

\frac{(x-0)^{2}}{1^{2}} +\frac{(y-(-2))^{2}}{3^{2}} = 1

\frac{x^{2}}{1} +\frac{(y+2)^{2}}{9} = 1

3 0
4 years ago
Which equation could represent the relationship shown in the scatter plot?
Nostrana [21]
The y-intercept has to be close to 10 because that's the one closest to the point closest to the y-axis. Therefore it has to be the last one.

Hope this helps :)


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3 years ago
Consider u have a 6 side dice what are the probabilities of It landing on 4
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You have a 1 in 6 chance
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