Answer:
Diploid.
Explanation:
DNA is present in the genetic material of all the eukaryotic and prokaryotic organisms.The eukaryotic genome contains DNA wraps around the histone proteins. Multiple distinct chromosomes are present in the eukaryote genome.
The eukaryotic genome are generally linear structure with the two copies of each chromosome. This makes the eukaryotic genome as diploid structure.
Thus, the correct answer is option (1).
Lactose because it is a sugar made up of galactose and glucose.
Answer:
they bind to protein-coupled transmembrane receptors with higher complexity than those found in prokaryotes
Explanation:
G-proteins are proteins found inside the cells that function as molecular switches which are activated by binding to guanosine triphosphate (GTP), while they are inactive by binding to guanosine diphosphate (GDP). The G-proteins bind to G-protein-coupled transmembrane receptors (GPCRs) in the cytoplasmic region. The GPCRs are a very diverse group of proteins that are activated by extracellular molecules ranging from small peptides to large proteins, including pheromones, neurotransmitters, light-sensitive compounds, etc, thereby allowing them to respond to diverse stimuli from the extracellular environment. In consequence, it is reasonable to suppose that the signaling pathways in which G proteins are involved have a higher complexity level than those observed in primitive prokaryotic organisms.
Can I see the picture that you are talking about please
Ans.
The codons show genetic codes, made up of triplet of nucleotides in DNA or RNA that code for specific amino acids. The different codes can code for a same a amino acid. When a substitutional mutation occurs in genetic material, it shows substitution of one nucleotide pair for another and leads to formation of a different codon.
The first mutation that leads to CAU to CAC, it will not show any potential damage as both CAU and CAC codons code for histidine amino acid.
The second mutation that leads to UGU to UGC will also not show any damage to protein as both of these codons code for cysteine amino acid.
The third codon, that results UCU to UUU will cause a potential damage to protein as UUU codes for phenyl alanine (an aromatic, non-polar amino acid) and UCU codes for serine (a polar amino acid).
Thus, the correct answer is 'option C).' as in a protein, substitution of serine with phenylalanine will lead to change in structure and function of that protein.
