Answer:
![2.23\times10^4](https://tex.z-dn.net/?f=2.23%5Ctimes10%5E4)
Step-by-step explanation:
In order to get the answer to this question you need to turn the scientific notations into standard form then subtract the two standard forms.
![(2.2\times10^{-4})-(3\times10^2)](https://tex.z-dn.net/?f=%282.2%5Ctimes10%5E%7B-4%7D%29-%283%5Ctimes10%5E2%29)
Turn the notations into standard form:
![2.2\times10^{-4} = .00022](https://tex.z-dn.net/?f=2.2%5Ctimes10%5E%7B-4%7D%20%3D%20.00022)
![3\times10^2=300](https://tex.z-dn.net/?f=3%5Ctimes10%5E2%3D300)
![.00022-300=22300](https://tex.z-dn.net/?f=.00022-300%3D22300)
![=22300](https://tex.z-dn.net/?f=%3D22300)
Turn into notation form:
![22300 = 2.23\times10^{4}](https://tex.z-dn.net/?f=22300%20%3D%202.23%5Ctimes10%5E%7B4%7D)
Hope this helps.
1.5 but you can’t get half a person
21 - 4x = 108
<em><u>Subtract 21 from both sides</u></em>
-4x = 87
<em><u>Divide both sides by -4</u></em>
x = -21.75
Answer:
<em>x = 2</em>
Step-by-step explanation:
<u>Exponential Equations</u>
Solve:
![5^{2x-1}+5^{x+1}=250](https://tex.z-dn.net/?f=5%5E%7B2x-1%7D%2B5%5E%7Bx%2B1%7D%3D250)
Separate each exponential:
![5^{2x}5^{-1}+5^{x}5^{1}=250](https://tex.z-dn.net/?f=5%5E%7B2x%7D5%5E%7B-1%7D%2B5%5E%7Bx%7D5%5E%7B1%7D%3D250)
Operating:
![\displaystyle \frac{5^{2x}}{5}+5^{x}5=250](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7B5%5E%7B2x%7D%7D%7B5%7D%2B5%5E%7Bx%7D5%3D250)
Multiplying by 5:
![5^{2x}+25\cdot5^x=1250](https://tex.z-dn.net/?f=5%5E%7B2x%7D%2B25%5Ccdot5%5Ex%3D1250)
Rearranging:
![5^{2x}+25\cdot5^x-1250=0](https://tex.z-dn.net/?f=5%5E%7B2x%7D%2B25%5Ccdot5%5Ex-1250%3D0)
Recall that:
![5^{2x}=(5^{x})^2](https://tex.z-dn.net/?f=5%5E%7B2x%7D%3D%285%5E%7Bx%7D%29%5E2)
![(5^{x})^2+25\cdot5^x-1250=0](https://tex.z-dn.net/?f=%285%5E%7Bx%7D%29%5E2%2B25%5Ccdot5%5Ex-1250%3D0)
Calling
![y=5^{x}:](https://tex.z-dn.net/?f=y%3D5%5E%7Bx%7D%3A)
![y^2+25y-1250=0](https://tex.z-dn.net/?f=y%5E2%2B25y-1250%3D0)
Factoring:
![(y-25)(y+50)=0](https://tex.z-dn.net/?f=%28y-25%29%28y%2B50%29%3D0)
There are two possible solutions:
y=25
y=-50
Since
![y=5^{x}](https://tex.z-dn.net/?f=y%3D5%5E%7Bx%7D)
y cannot be negative, thus:
![5^{x}=25=5^2](https://tex.z-dn.net/?f=5%5E%7Bx%7D%3D25%3D5%5E2)
The solution is:
x = 2
Answer:
16f/h
+ 112/h
Step-by-step explanation:
thats is I just get it a week ago on a test