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alexira [117]
3 years ago
9

X/7=3/5 so x=??????????????????

Mathematics
2 answers:
g100num [7]3 years ago
6 0
X = 3 --->  3*7 = 21 so 5x = 21   
7    5

5x = 21   this equals 4.2
5       5     

frosja888 [35]3 years ago
5 0
By using cross multiplication x= 3×7÷5=4.2
the answer is 4.2
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Hi! ❤️ , im looking for some help here. ill give brainliest if able to.
Alexeev081 [22]

Answer:

A. 2^11

Step-by-step explanation:

(They are basically asking what's 2^4 × 2^7, but with more words.)

I usually do each exponent individually:

2^4 is the same as 2 × 2 × 2 × 2 = 16 (or you could have read the text to figure that out)

2^7 is the same as 2 × 2 × 2 × 2 × 2 × 2 × 2 = 128

Then just multiply 128 and 16 to get 2,048, and see which option also gives you 2,048.

BUT, you can also:

(Combine the exponents together to get your answer. Just remember that if it's multiplication you add them, and if it's division you subtract them.)

2^4 × 2^7

4 + 7 = 11

2^11 (This equals 2,048 btw. You don't even have to check all the options to get the answer).

Hope this helps friend :)

The last part I learned from another user, while answering one of your other questions. I personally find this mind blowing, lol.

4 0
2 years ago
The following graph indicates a _______________.
inna [77]
Bfh ju yrdfhjjgfjkiytdcbnkl
4 0
2 years ago
A grocery store gives a$10 gift card to every 25th customer and a $20 to every 69th customer. Which customer will be the first t
alina1380 [7]

Answer:

First answer:

1725 customer.

Second Answer:

$690

Step-by-step explanation:

What you have to do is find the LCM(Least Common Multiple) of both 25 and 69.

8 0
3 years ago
Find the error with this proof and explain how it mat be corrected in order to clearly prove the equation.
enyata [817]

Answer:

Step-by-step explanation:

It is true that for any given odd integer, square of that integer will also be odd.

i.e if m is and odd integer then m^{2} is also odd.

In the given proof the expansion for (2k + 1)^{2} is incorrect.

By definition we know,

(a+b)^{2} = a^{2} + b^{2} + 2ab

∴ (2k + 1)^{2} = (2k)^{2} + 1^{2} + 2(2k)(1)\\(2k + 1)^{2} = 4k^{2} + 1 + 4k

Now, we know 4k^{2} and 4k will be even values

∴4k^{2} + 1 + 4k will be odd

hence (2k + 1)^{2} will be odd, which means m^{2} will be odd.

7 0
3 years ago
How to estimate 5.4 x 0.1
snow_tiger [21]
I think it’s 0.54. But I’m not sure if that’s right
7 0
3 years ago
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