Which 30 60 90 triangle is labled with the correct side length ratio

5r^2-13r-6=0 How do I solve this

frosja888 [35]

$5 {r}^{2} - 13r - 6 = 0 \\ a = 5 \\ b = - 13 \\ c = - 16 \\$

r= -(-13)±>

$\sqrt{( - 13) {}^{2} } - 4.5( - 6)$

2.5

r= 13±17

10

r=13+17

10

r=13-17

10

$r = 2 \\ r = \frac{ - 2}{5}$

$this \: the \: answer \: your \: question \\ \\ mark \: me \: as \: a \: brainlist \: plz$

7 0

3 years ago

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What is the solution if any, to the inequality 3-l4-nl>1?

atroni [7]

Answer:

The solution to the inequality is all real values of n that respect the following condition: 2 < n < 6

Step-by-step explanation:

First, we need to separate the modulus from the rest of equation. So

3-l4-nl>1

-|4-n|>1-3

-|4-n|>-2

Multiplying everything by -1.

|4-n|<2

How to solve:

|x| < a means that -a<x<a

In this question:

|4-n|<2

-2<4-n<2

This means that:

4 - n > -2

-n > -6

Multiplying by -1

n < 6

And

4 - n < 2

-n < -2

Multiplying by 1

n > 2

Intersection:

Between n > 2 and n < 6 is 2 < n < 6

So the solution to the inequality is all real values of n that respect the following condition: 2 < n < 6

8 0

3 years ago

PLD HELP ME I WILL FAIL PLSx

elena55 [62]

Answer:

19.4236 is your answer

Step-by-step explanation:

8 0

3 years ago

The principal of a large high school wants to know if students spend more than 1 hour doing homework per night, on average. To i

MrRissso [65]

Answer:

If we define the random variable X ="time spend by the students doign homework"

And we want to tes t is students spend more than 1 hour doing homework per night, on average (alternative hypothesis), so then the system of hypothesis for this case are:

Null hypothesis: $\mu \leq 1$

Alternative hypothesis: $\mu >1$

And they wnat to use a sample size of n = 100 and a significance level of 0.05

Step-by-step explanation:

Previous concepts

A hypothesis is defined as "a speculation or theory based on insufficient evidence that lends itself to further testing and experimentation. With further testing, a hypothesis can usually be proven true or false".

The null hypothesis is defined as "a hypothesis that says there is no statistical significance between the two variables in the hypothesis. It is the hypothesis that the researcher is trying to disprove".

The alternative hypothesis is "just the inverse, or opposite, of the null hypothesis. It is the hypothesis that researcher is trying to prove".

Solution to the problem

If we define the random variable X ="time spend by the students doign homework"

And we want to tes t is students spend more than 1 hour doing homework per night, on average (alternative hypothesis), so then the system of hypothesis for this case are:

Null hypothesis: $\mu \leq 1$

Alternative hypothesis: $\mu >1$

And they wnat to use a sample size of n = 100 and a significance level of 0.05

7 0

3 years ago

Write a multiplication fact that goes with this division fact. 30 ÷ 5 = 6

34kurt

5 times 6 = 30 hope this helped

8 0

3 years ago

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