There are 10 balls in the Urn Total.
Red: 6
Green: 4
Question One: The probability that five red and two green is selected is likely. (as that is over half for both)
Question Two: Impossible. There is only 6 red balls, and 7 are taken from the urn. Thus it would at most be possible for 6 red and 1 green.
Question Three: At least four is likely, as there is more red then green in the Urn.
Hope I helped!
(Mark Brainliest if you can please!)
First get the factors of 24: 2*2*2*3Then the factors of 9: 3*3 Comparing the factors, the GCF is 3 Then you can rewrite the expression: 3*8 + 3*3 At this point, I'm not sure whether what you mean is really distributive property or not since this case is more of a factoring. 3*(8+3)
Answer:
c = 6
Step-by-step explanation:
1/2 (2(4) + 4) = 3(4) - c
1/2 (8 + 4) = 12 - c
1/2 (12) = 12 - c
6 = 12 - c
-6 = -c
c = 6
Answer:
Exact Form : 6/5
Decimal Form : 1.2
Mixed Nuumber Form ; 1 1/5
Multiply the first equation by two to get 2x + 2y = 4.
Subtract the second equation from the first equation to get -3y = -12
y = 4.
Plug y back in to get x = -2.