<h3 /><h3>▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄</h3><h3>Required Solution :</h3>
Let the first even number be 'x' & the second even number be (x + 2)
<u>According to the Question</u>,
⇒x + (x + 2) = 34
⇒x + x + 2 = 34
⇒2x + 2 = 34
⇒2x = 34 - 2
⇒2x = 32
⇒x = 32/2
⇒x = 16
⇒First even number = x = 16
⇒Second even number = (x + 2) = 16 + 2 = 18
<u>∴</u><u> </u><u>The t</u><u>wo consecutive even n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u>s</u><u> are 16 & 18</u> ...!
<h3>Verefication : </h3>
As, In our Question it was given that "The sum of two consecutive even numbers is thirty-four". So, as we got our two consecutive even numbers as 16 & 18 ... By this, we can say that these both even numbers should be equals to 34, i.e., 16 + 18 = 34. Hence, The equation which we formed is correct ...!
<h3>▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄▄</h3>
1 2 3
1 2 3 1 2 3 1 2 3
123 123 123 123 123 123 123 123 123
3 3 3 3 3 3 3 3 3
3(9)
27
Answer:
15 fifths
Step-by-step explanation:
Answer:
2bm + 7an
Step-by-step explanation:
Multiply.
8bm - 6an - bm + 5an - 5bm + 8an
Combined like terms:
8bm - <em>6an</em> - bm + <em>5an</em> - 5bm + <em>8an</em>
= 2bm + 7an
