Please help me find the area of this figure! Thanks!!
1 answer:
Answer:
Step-by-step explanation:
Figure consists of three parts; one Triangle , one rectangle and a square.
<u>Triangle: </u>
Base = b = 13+9 = 22 cm
height = 16 cm
<u>Rectangle 1: </u>
length = 14 cm
Width = 4 cm
Area of R1 = length * width = 14 * 4 = 56 cm²
<u>Area of Square R2:</u>
side = 8 cm
Area of square = side * side = 8 * 8 = 64 cm²
Area of shaded region = 176 + 56 + 64 = 296 cm²
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Answer:
(4,-8) and (4, 12)
Step-by-step explanation:
The equation of the hyperbola given is:
The general form of this hyperbola would be:
Thus, we can see that:
a^2 = 64
a = 8
and
b^2 = 36
b = 6
The distance from one focus to center is called "c", it goes by formula:
Let's find c:
This is a vertical hyperbola and the center is found from the x and y's on the numerator:
(y-2)^2 means y = 2
(x-4)^2 = x = 4
Center is (4, 2)
We go 10 units vertically up, so from y = 2 , ten units up makes it y = 12
x = 4 and y = 12
(4,12)
We go 10 units vertically down, so from y =2, ten units down makes it y = -8
x = 4 and y = -8
(4, -8)
<u>Foci coordinates:</u>
<u>(4,12) and (4,-8)</u>