Solve the equasion<br><br>2y-10y

Whoever reads this I hope you have a great day and don't forget to smile :)<br> #spread positivity

svetlana [45]

Answer: ty! I hope you do too ✨

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Will give brainliest NEED HELP can some explain how to do this THANKS :D

arlik [135]

Answer:

(x + 13, y + 7)

Step-by-step explanation:

Hello there!

In order to find what the translation rule is, we need to find how much it move to the right/left and up/down

In this case, the line segment VW moved up 7 and to the right by 13

We can get this by checking how far apart the points are

I checked how far apart V and V prime

(V prime is the green V. When a point is primed, its just saying that the point has gone through translation, rotation, dilation, or reflection)

V is 13 units to the left of V prime and 7 units below V prime

This means that, to go from line VW to line V prime W prime, you need to shift the line up 7 units and to the right 13 units

So, the translation rule is (x + 13, y + 7)

*If you don't understand, tell me in the comments, I will try to explain further to your understanding. Thank you, and have a great rest of your day :)*

3 0

2 years ago

The area of the shaded triangle is 5x2+3x-4. What is the area of the entire figure?

Phoenix [80]

The answer will be 2 cuz you multiply them at the answers

3 0

4 years ago

Help!! Lots of points!!

Yanka [14]

Answer:

the correct answer would b (B)

7 0

4 years ago

Read 2 more answers

Sand is leaking through a small hole at the bottom of a conical funnel at the rate of 12cm3/s . if the radius of the funnel is 8

Bezzdna [24]

Answer:

h ≅ 16.29 cm

$\mathbf{\dfrac{dh}{dt}= -0.1809 \ cm/s}$

Step-by-step explanation:

From the conical funnel;

Let the adjacent line at the base of the cone be radius (r) and the opposite ( vertical length) be the height (h)

Then;

$tan \theta= \dfrac{r}{h}$

$tan \theta= \dfrac{8}{16}$

$tan \theta= \dfrac{1}{2}$

∴

$\dfrac{r}{h} = \dfrac{1}{2}$

$r = \dfrac{h}{2}$

The volume (V) of the cone is expressed as:

$V = \dfrac{1}{3}\pi r ^2 h$

$V = \dfrac{1}{3}\pi (\dfrac{h}{2})^2 h$

$V = \dfrac{\pi h^3}{3\times 4}$

$\dfrac{dv}{dt} = \dfrac{3 \pi h^2}{3 \times 4} \dfrac{dh}{dt}$

$\dfrac{dv}{dt} = \dfrac{ \pi h^2}{4} \dfrac{dh}{dt}$

Given that:

$\dfrac{dv}{dt} = 12 \pi$

Then:

$-12 \pi = \dfrac{ \pi h^2}{4} \dfrac{dh}{dt}$

$- \int 48 \ dt = \int h^2 \ dh$

$\dfrac{h^3}{3}= -48 t + c$

$At \ t = 0 \ ; h = 0$

∴

$\dfrac{0^3}{3} = -48(0) + c$

c = 0

So;

$\dfrac{h^3}{3}= -48 t + 0$

$\dfrac{h^3}{3}= -48 t$

t = 30

$\implies h = (-48(30))^{1/3}$

h = 16.2865

h ≅ 16.29 cm

Thus;

from $-12 \pi = \dfrac{ \pi h^2}{4} \dfrac{dh}{dt}$

$\dfrac{-12 \pi} { \dfrac{ \pi h^2}{4} } =\dfrac{dh}{dt}$

$\dfrac{dh}{dt} = \dfrac{-12 \pi} { \dfrac{ \pi h^2}{4} }$

$\dfrac{dh}{dt}=\dfrac{-12 \times 4} { {16.29^2} }$

$\mathbf{\dfrac{dh}{dt}= -0.1809 \ cm/s}$

7 0

3 years ago

Solve the equasion2y-10y