The reactant being used up is called limiting reagent as it limits the total amount of product produced.
if 4 units of HCL gives 2 units of Cl therefore
4:2
0.98:x
x=(0.98*2) /4
x=0.49L
Answer:

Explanation:
We will need a balanced equation with masses, moles, and molar masses, so let’s gather all the information in one place.
Mᵣ: 44.01
C₃H₈ + 5O₂ ⟶ 3CO₂ + 4H₂O
n/mol: 1.5
1. Calculate the moles of CO₂
The molar ratio is 3 mol CO₂:1 mol C₃H₈

2. Calculate the mass of CO₂.

Number 2 lower entropy and higher entropy
The answer to the question is D
Answer:
1 x 10⁻¹¹ M
Explanation:
<u>(Step 1)</u>
Determine the pH.
pH = -log[H⁺]
pH = -log[1 x 10⁻³ M]
pH = 3
<u>(Step 2)</u>
Determine the pOH.
pH + pOH = 14
3 + pOH = 14
pOH = 11
<u>(Step 3)</u>
Determine the hydroxide (OH⁻) concentration.
[OH⁻] = 10^-pOH
[OH⁻] = 10⁻¹¹
[OH⁻] = 1 x 10⁻¹¹ M