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ANTONII [103]
3 years ago
11

Why would you need to heat the hydrate up to 250 degrees if water boils at 100 degrees Celsius? Do you think that the boiling po

int of water in a hydrate might be different then pure water? Why?
Chemistry
1 answer:
sergeinik [125]3 years ago
8 0

Explanation:

The pure form of water has a boiling point of 100°C. Boiling point is a physical property of matter and it shows that at such temperature, a liquid substance will change state to vapor.

Pure water is made up of 2 atoms of hydrogen and 1 atom of oxygen. The only intermolecular forces between them is the hydrogen bonds that must be broken for the water to boiling off.

In hydrate, water is present in another form. The water is attached to another compound.

For a pure liquid, the they have reasonably constant boiling point and low boiling range.

Impurities such as the other part of the hydrate causes the elevation of the boiling point and the widening of the boiling range for impure substances.

We are no longer dealing with just hydrogen bonds, other molecular interactions are now involved and they need to be accounted for.

learn more:

Pure substances brainly.com/question/1832352

#learnwithBrainly

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Calculate the pH of each solution at 25∘C
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Answer: pH of HCl =5, HNO3 = 1,

NaOH = 9, KOH = 12

Explanation:

pH = -log [H+ ]

1. 1.0 x 10^-5 M HCl

pH = - log (1.0 x 10^-5)

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2. 0.1 M HNO3

pH = - log (1.0 x 10 ^ -1)

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pH + pOH = 14

Therefore , pH = 14 - 5 = 9

4. 0.01 M KOH

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8 0
3 years ago
Write a balanced equation for the complete combustion of 2,3-dimethylbutane. use the molecular formula for the alkane (c before
Nuetrik [128]

2C_6H_14 + 19O_2 → 12CO_2 + 14H_2O

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(CH_3)_2CHCH(CH_3)_2

<em>Step 2</em>. Write the <em>molecular formula</em>.

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<em>Step 3</em>. Write the <em>unbalanced chemical equation</em>.

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<em>Step 4</em>. Pick the <em>most complicated-looking formula</em> (C_6H_14) and balance its atoms (C and H).

<em>1</em>C_6H_14 + O_2 → <em>6</em>CO_2 + <em>7</em>H_2O

<em>Step 5</em>. Balance the <em>remaining atoms</em> (O).

1C_6H_14 + (<em>19/2</em>)O_2 → 6CO_2 + 7H_2O

Oops! <em>Fractional coefficients</em>!

<em>Step 6</em>. <em>Multiply all coefficients by a number</em> (2) to give integer coeficients..

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Answer:

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