Two sets of Christmas lights are available. For set A, when one bulb is removed, the remaining bulbs remain illuminated. For set
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Answer:
The kinetic coefficient of friction of the crate is 0.235.
Explanation:
As a first step, we need to construct a free body diagram for the crate, which is included below as attachment. Let supposed that forces exerted on the crate by both workers are in the positive direction. According to the Newton's First Law, a body is unable to change its state of motion when it is at rest or moves uniformly (at constant velocity). In consequence, magnitud of friction force must be equal to the sum of the two external forces. The equations of equilibrium of the crate are:
(Ec. 1)
(Ec. 2)
Where:
- Pushing force, measured in newtons.
- Tension, measured in newtons.
- Coefficient of kinetic friction, dimensionless.
- Normal force, measured in newtons.
- Weight of the crate, measured in newtons.
The system of equations is now reduced by algebraic means:
And we finally clear the coefficient of kinetic friction and apply the definition of weight:
If we know that ,
,
and
, then:
The kinetic coefficient of friction of the crate is 0.235.
Distance traveled by the ball is given by
here we know that
speed = 20 m/s
times = 0.25 s
now we have
so ball will travel 5 m distance in the given interval of time