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2 years ago

13

Which of the following are true about renewable resources?

1 answer:

Oksana_A [137]2 years ago

6 0

Answer:

option A

Explanation:

renewable resources are replenishable that means they can't be depleted

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A ball was dropped from a height of 10 feet. Each time it hits the ground, it bounces 4/5 of its previous height. Find the total

Shtirlitz [24]

Answer:

d = 90 ft

Explanation:

As we know that after each bounce it reaches to 4/5 times of initial height

so we can say

$h_2 = \frac{4}{5}h$

so the distance covered is given as

$d = h + 2(\frac{4}{5}h) + 2(\frac{4}{5})^2h + 2(\frac{4}{5})^3h........$

here we know that

h = 10 feet

$d = h + 2(\frac{4}{5}h)(1 + \frac{4}{5} + (\frac{4}{5})^2 + ...........)$

$d = 10 + 2(\frac{4}{5}(10))(\frac{1}{1 - \frac{4}{5}})$

$d = 90 ft$

8 0

3 years ago

A flywheel with a diameter of 1.63 m is rotating at an angular speed of 79.9 rev/min. (a) What is the angular speed of the flywh

Studentka2010 [4]

Answer:

(a) 8.362 rad/sec

(b) 6.815 m/sec

(c) 9.446 $rad/sec^2$

(d) 396.22 revolution

Explanation:

We have given that diameter d = 1.63 m

So radius $r=\frac{d}{2}=\frac{1.63}{2}=0.815m$

Angular speed N = 79.9 rev/min

(a) We know that angular speed in radian per sec

$\omega =\frac{2\pi N}{60}=\frac{2\times 3.14\times 79.9}{60}=8.362rad/sec$

(b) We know that linear speed is given by

$v=r\omega =0.815\times 8.362=6.815m/sec$

(c) We have given final angular velocity $\omega _f=675rev/min$

And $\omega _i=79.9rev/min$

Time t = 63 sec

Angular acceleration is given by $\alpha =\frac{\omega _f-\omega _i}{t}=\frac{675-79.9}{63}=9.446rad/sec^2$

(d) Change in angle is given by

$\Theta =\frac{1}{2}(\omega _i+\omega _f)t=\frac{1}{2}(675+79.9)\times 1.05=396.22rev$

7 0

3 years ago

Which characteristic should a good scientific question have?

Brilliant_brown [7]

The best answer to this question is D. a god scientific question should be based on observations instead of just imagination.

Hope this helps.

7 0

3 years ago

Read 2 more answers

The force of the added water produces a torque on the dam. In a simple model, if the torque due to the water were enough to caus

Fittoniya [83]

Answer:

The appropriate response is " $\tau=\frac{1}{6} PgLh^3$ ". A further explanation is described below.

Explanation:

The torque ( $\tau$ ) produced by the force on the dam will be:

⇒ $d \tau=XdF$

On applying integration both sides, we get

⇒ $\tau = \int_{0}^{a}x pgL(h-x)dx$

⇒ $= pgL\int_{0}^{h}(h-x)dx$

⇒ $=pgL[\frac{h^3}{2} -\frac{h^3}{3} ]$

⇒ $=\frac{1}{6} PgLh^3$

8 0

2 years ago

A spaceship from a friendly, extragalactic planet flies toward Earth at 0.203 0.203 times the speed of light and shines a powerf

Serjik [45]

Answer:

567.321nm

Explanation:

See attached handwritten document for more details

7 0

3 years ago

Read 2 more answers