A 70 kg man is walking at a speed of 2 m/s. What is his Kinetic Energy?
2 answers:
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The change in mechanical energy caused by the dissipative resistance force is equal to, difference between the potential energy and kinetic energy of the object.
Potential energy of the object, P.E = mgh
m is mass of the object = 10 kg
g is acceleration due to gravity = 9.8 m/s²
h= height from which it is dropped =50 m
Substituting the value we get,
P.E = 10×9.8×50 = 4900 J
Kinetic energy of the object, K.E =
v is the velocity of the object = 26 m/s²
K.E = (1/2)×10×(26)²
= 3380 J
Change in mechanical energy caused by dissipative force = P.E ₋ K.E
= 4900 ₋ 3380 = 1520 J
To develop this problem it is necessary to apply the concepts related to the Cross Product of two vectors as well as to obtain the angle through the magnitude of the angles.
The vector product between the Force and the radius allows us to obtain the torque, in this way,
Therefore the torque on the particle about the origen is 50k
PART B) To find the angle between two vectors we apply the definition of the dot product based on the vector quantities, that is,
Therefore the angle between the ratio and the force is 103.88°