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4 years ago

A 70 kg man is walking at a speed of 2 m/s. What is his Kinetic Energy?

Physics

2 answers:

Ilya [14]4 years ago

8 0

Kinetic energy = 1/2 (mass) (speed squared)

KE = 1/2 (70kg) (2m/s)^2

KE = (35 kg) (4 m^2/s^2)

KE = (140) kg-m^2/s^2

That's 140 Newton-meter

140 Joules

den301095 [7]4 years ago

5 0

140 Jules. Is the correct answer

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Your washer has power of 450 watts, and your dryer has a power of 3000

bulgar [2K]

Answer:

4950 watt hours.

Explanation:

450*1 + 3000*1.5 = 4950w

3 0

2 years ago

15.

gizmo_the_mogwai [7]

(a) $4.8\cdot 10^{-19} C$

The radius of the trajectory of a charged particle moving perpendicular to a magnetic field is given by

$r=\frac{mv}{qB}$

where

m is the mass of the particle

q is its charge

v is its velocity

B is the strength of the magnetic field

In this problem, we have:

$m=2.66\cdot 10^{-26} kg$

$v=5.00\cdot 10^6 m/s$

B = 1.20 T

r = 0.231 m

Solving for q, we find its charge:

$q=\frac{mv}{rB}=\frac{(2.66\cdot 10^{-26})(5.00\cdot 10^6)}{(0.231)(1.20)}=4.8\cdot 10^{-19} C$

(b) 3

The charge of an electron is

$e=1.6\cdot 10^{-19}C$

While the charge of this oxygen ion is

$q=4.8\cdot 10^{-19}C$

So, the ratio between the two charges is

$\frac{q}{e}=\frac{4.8\cdot 10^{-19}}{1.6\cdot 10^{-19}}=3$

(c) Because an ion is an atom that has gained/lost an integer number of electrons

An ion is an atom that has gained/lost an integer number of electrons. In this particular case, we see that the charge of the oxygen ion is 3 times that of the electron: this means that the ion has gained/lost exactly 3 electrons.

The ratio found in part (b) cannot be a fraction, because that would mean that the atom has gained/lost a fractional number of electrons: but this is impossible, since the electron is a fundamental particle so it cannot be "divided", therefore the ratio must be an integer.

7 0

3 years ago

A pitched ball is hit by a batter at a 47◦ angle. It just clears the outfield fence, 98 m away. The acceleration of gravity is 9

musickatia [10]

Answer:u=31.02 m/s

Explanation:

Given

launch angle of ball $\theta =47^{\circ}$

Range of ball $R=98 m$

considering ball to be a Projectile

Range of Projectile is given by

$R=\frac{u^2\sin 2\theta }{g}$

Where $u=initial\ Velocity$

$\theta =launch\ angle$

$g=acceleration\ due\ to\ gravity$

$98=\frac{u^2\sin 2(47)}{9.8}$

$98\times 9.8=u^2\sin (94)$

$u^2=\frac{960.4}{sin (94)}$

$u^2=962.74$

$u=31.02 m/s$

5 0

3 years ago

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kobusy [5.1K]

◦•●◉✿hello friend ur answer✿◉●•◦

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3 years ago

Any form of stored energy is described as

seropon [69]

Potential energy , hope this helps :)

4 0

2 years ago