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3 years ago

A sprinter speeds up to 3 m/s during the last 2 seconds of the race with an

Physics

1 answer:

quester [9]3 years ago

4 0

Answer:

The initial speed of the sprinter was 2.2 m/s

Explanation:

Constant Acceleration Motion

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

The following relation applies:

$v_f=v_o+at$

Where a is the constant acceleration, vo the initial speed, vf the final speed, and t the time.

The sprinter speeds up from an unknown initial speed to vf=3 m/s in t=2 seconds with an acceleration of $a=0.4~m/s^2$ .

To find the initial speed, we solve the equation for vo:

$v_o=v_f-at$

Substituting the values:

$v_o=3-0.4*2$

$v_o=3-0.8$

$v_o=2.2~m/s$

The initial speed of the sprinter was 2.2 m/s

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3 years ago

Assuming typical speeds of 8.5 km/s and 5.5 km/s for P and S waves, respectively, how far away did the earthquake occur if a par

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Answer:

The earthquake occurred at a distance of 1122 km

Explanation:

Given;

speed of the P wave, v₁ = 8.5 km/s

speed of the S wave, v₂ = 5.5 km/s

The distance traveled by both waves is the same and it is given as;

Δx = v₁t₁ = v₂t₂

let the time taken by the wave with greater speed = t₁

then, the time taken by the wave with smaller speed, t₂ = t₁ + 1.2 min, since it is slower.

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v₁t₁ = v₂t₁ + 72v₂

v₁t₁ - v₂t₁ = 72v₂

t₁(v₁ - v₂) = 72v₂

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3 years ago

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Lina20 [59]

Answer:

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There are 660 cm in 1 m.

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