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zlopas [31]
3 years ago
6

A sprinter speeds up to 3 m/s during the last 2 seconds of the race with an

Physics
1 answer:
quester [9]3 years ago
4 0

Answer:

<em>The initial speed of the sprinter was 2.2 m/s</em>

Explanation:

<u>Constant Acceleration Motion</u>

It's a type of motion in which the velocity of an object changes by an equal amount in every equal period of time.

The following relation applies:

v_f=v_o+at

Where a is the constant acceleration, vo the initial speed, vf the final speed, and t the time.

The sprinter speeds up from an unknown initial speed to vf=3 m/s in t=2 seconds with an acceleration of a=0.4~m/s^2.

To find the initial speed, we solve the equation for vo:

v_o=v_f-at

Substituting the values:

v_o=3-0.4*2

v_o=3-0.8

v_o=2.2~m/s

The initial speed of the sprinter was 2.2 m/s

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Answer:

Work done is 0.

Explanation:

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A vehicle moving at 5m/s, i . what should be the constant declaration in order to stop it within 15m? ii. How long it takes to s
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Answer:

Refer to the attachment for solution (1).

<h3><u>Calculating time taken by it to stop (t) :</u></h3>

By using the second equation of motion,

→ v = u + at

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  • u denotes initial velocity
  • t denotes time
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→ 0 = 5 + (-5/6)t

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→ 0 + (5/6)t = 5

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