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3 years ago

Calculate the normal force of a 1,200 kg boulder resting on the ground

Physics

2 answers:

Olin [163]3 years ago

4 0

Answer:

The normal force points upward and is 11,760 N

Explanation:

Resting on the ground = upward

1200 * 9.8 = 11, 760

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Darya [45]3 years ago

3 0

Answer:

11760N

Explanation:If the boulder is at rest and not going up or down we would take the 1200 kg and multiply it by 9.8 because

(sum)F = ma and since a is 0 the equation goes to

Fn - mg= 0 an that simplifies to

Fn=mg

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A solid conducting sphere (radius = 5.0 cm) has a charge of 0.25 nC distributed uniformly on its surface. If point A is located

nadezda [96]

Answer:

$\Delta V = 30V$

Explanation:

give data:

inside diameter = 5.0 cm

charge q = 0.25 nC

Outside diameter = 15 cm

potential V at inside sphere is = $V=\frac{kq}{R}$

potential V at outside sphere is = $V=\frac{kq}{r}$

k is constant whose value is = $8.99 *10^{9}Nm^{2}/c^2$

then potential difference between two point is

$\Delta V = kq \left [\frac{1}{R}-\frac{1}{r} \right ]$

$\Delta V = 9*10^{9}*0.25*10^{-9} \left [\frac{1}{0.05}-\frac{1}{0.15} \right ]$

$\Delta V = 30V$

6 0

3 years ago

You are designing a circuit to power a night light, and want to keep the light level as low as possible. The wire you use can ha

Minchanka [31]

Answer:

Total 20 number of resistors are required to connect in series

Explanation:

As we know by Ohm's law that potential difference across the resistor is the product of resistance and current flowing in it

So we have

$V = i R$

here we know that

V = 120 V

i = 3 A

so we have

$R = \frac{120}{3} = 40 ohm$

now we know that all the resistors are connected in series and each resistor is of 2 ohm

so total N number of resistors are required

$2 N = 40$

$N = 20$

5 0

2 years ago

8. Using a ramp 6 meters long, workers apply an effort force of 1250 N to move a

Alexxandr [17]

The efficiency of the machine is 0.53 (53%).

Explanation:

The efficiency of a machine is given by:

$\eta = \frac{W_{out}}{W_{in}}$

where

$W_{out}$ is the output work

$W_{in}$ is the work in input

The output work is:

$W_{out}=F_L d_L = (2000)(2)=4000 J$

where

$F_L = 2000 N$ is the load

$d_L = 2 m$ is the distance covered by the load

The input work is:

$W_{in}=F_E d_E = (1250)(6)=7500 J$

where

$F_E = 1250 N$ is the effort force

$d_E = 6 m$ is the distance from the effort to the pivot

Solving for the efficiency,

$\eta=\frac{4000}{7500}=0.53$

So, the efficiency of the machine is 0.53 (53%).

Learn more about work:

brainly.com/question/6763771

brainly.com/question/6443626

#LearnwithBrainly

8 0

3 years ago

Which of the following refers to the increasing size of deserts worldwide? A. disintegration B. desertification C. decomposition

algol [13]

the answer is B. desertification

7 0

3 years ago

Read 2 more answers

4. A tuning fork is held over a resonance tube, and resonance occurs when the surface of the water is 12 cm below the top of the

Mrac [35]

As we know that speed of sounds is given as

$v = 332 + 0.6t$

here we know that

t = 23 degree C

now from above equation we will have

$v = 332 + (0.6)(23)$

$v = 345.8 m/s$

now we also know that distance between two consecutive resonance length is half of the wavelength

$L_2 - L_1 = \frac{\lambda}{2}$

$34 - 12 = \frac{\lambda}{2}$

$\lambda = 44 cm$

now we know that

$frequency = \frac{speed}{wavelength}$

$f = \frac{345.8}{0.44} = 786 Hz$

so frequency will be 786 Hz

7 0

2 years ago