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Ann [662]
3 years ago
5

(58) The pressure of a gas in a tank is 422 psi at

Chemistry
1 answer:
wel3 years ago
5 0
<h3>Answer:</h3>

1270 Psi

<h3>Explanation:</h3>

<u>We are given;</u>

  • Pressure in the tank, P₁ as 422 psi
  • Temperature in the tank, T₁ as 20.0 K
  • New temperature in the tank, T₂ as 60.0 K

We are required to determine the pressure at 60.0 K

  • We are going to use the pressure law;
  • According to the pressure law, the pressure of a gas is directly proportional to  the temperature at constant volume.
  • That is; P\alpha T
  • Thus, \frac{P}{T}=constant
  • At different pressures and temperature;

\frac{P1}{T1} =\frac{P2}{T2}

  • Thus, rearranging the formula;

P2=\frac{P1T2}{T1}

Hence;

P1=\frac{(422Psi)(60K)}{20}

P1=1266Psi

Therefore;

P₂=1266 Psi

   = 1270 Psi

Thus, the pressure at 60.0 K is 1270 Psi

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strojnjashka [21]

Answer:

CO₃²⁻(aq)  +  2H⁺(aq) → CO₂ (g)  + H₂O (l)

Explanation:

The balanced reaction between Na2CO3 and HCl is given as;

Na₂CO₃ (aq) + 2 HCl (aq) → 2 NaCl (aq) + CO₂ (g) + H₂O (l)

The next step is o express the species as ions.

The complete ionic equation for the above  reaction would be;

2Na⁺(aq)  + CO₃²⁻(aq)  +  2H⁺(aq)  + 2Cl⁻(aq)   → Na⁺(aq)  + Cl⁻(aq)  + CO₂ (g)  + H₂O (l)

The next step is to cancel out the spectator ion ions; that is the ions that appear in both the reactant and product side unchanged.

The spectator ions are;  Na⁺ and Cl⁻

The net ionic equation is given as;

CO₃²⁻(aq)  +  2H⁺(aq) → CO₂ (g)  + H₂O (l)

7 0
3 years ago
For each chemical equation below, write the number of product molecules that will form from the reaction.
Gekata [30.6K]

Answer:

a. 5 moles of CO₂

b. 2 moles of NaCl

c. 3 moles of H₂CO₃

Explanation:

1a. Carbon reacts with oxygen to produce carbon dioxide according to equation below:

C + O₂ ----> CO₂

From the equation of reaction, one mole of carbon reacts with one mole of oxygen to produce one mole of carbon dioxide.

In the given reaction, therefore, 5 moles of carbon will only react with 5 moles of oxygen to produce 5 moles of carbon dioxide. Oxygen is in excess, carbon is the limiting reactant and 5 moles of carbon dioxide are produced. The equation is given below :

5 C + 6 O₂ ---> 5 CO₂

1b. Sodium reacts with chlorine to produce sodium chloride according to the equation below:

2 Na + Cl₂ ---> NaCl

From the equation of reaction, 2 moles of sodium reacts with one mole of chlorine to produce one mole of sodium chloride.

In the given reaction, therefore, 4 moles of sodium will react with only 2 moles of chlorine to produce 2 moles of sodium chloride. Chlorine is in excess, sodium is the limiting reactant and 2 moles of sodium chloride are produced. The equation is given as follows: 4 Na + 8 Cl₂ ---> 2 NaCl

1c. Carbon dioxide reacts with water to produce carbonic acid according to the equation: CO₂ + H₂O ---> H₂CO₃

From the equation of reaction one mole of carbon dioxide reacts with one mole of water to produce one mole of carbonic acid.

In the given reaction, therefore, 3 moles of carbon dioxide will react with only 3 moles of water to produce 3 moles of carbonic acid. Water is in excess, carbon dioxide is the limiting reactant and 3 moles of carbonic acid are produced. The equation is given as follows: 3 CO₂ + 4 H₂O ---> 3 H₂CO₃

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Given data:

Mass of copper (m)  = 20.0 g

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Final temperature = T2

Heat absorbed by copper (Q) = 475 J

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Q = mcΔT

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475 = 20*0.385*(T2-25)

62.08 = T2-25

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