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2 years ago

A 4 gram metal is heated and it's temperature changes from 25 degrees C to 35

Chemistry

2 answers:

iren [92.7K]2 years ago

7 0

Answer:

Explanation:

Answer in link below!

http://www.tiger-algebra.com/en/

mote1985 [20]2 years ago

6 0

Answer:

O60J

Explanation:

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I got c, just wondering was it right?

Talja [164]

Answer:

Yes you are right.

Explanation:

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1 year ago

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Which is the correctly balanced chemical equation for the reaction of KOH and H2SO4? Which is the net ionic equation for the rea

NeX [460]

Answer:

See explanation

Explanation:

A balanced chemical reaction equation has the same number of atoms of each element on both sides of the reaction equation.

Hence, for the reaction between KOH and H2SO4, the balanced chemical reaction equation is;

H2SO4(aq) + 2KOH(aq) ---------> K2SO4(aq) + 2H2O(l)

Complete ionic equation;

2H^+(aq) + SO4^2-(aq) + 2K^+(aq) +2OH^-(aq) -------> SO4^2-(aq) + 2K^+(aq) + 2H2O(l)

Net ionic equation;

2H^+(aq) + 2OH^-(aq) -------> 2H2O(l)

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2 years ago

The diagram below shows a gas sample being measured with an open-end mercury (Hg) manometer. If a barometer reads 730. 1 torr, w

IRISSAK [1]

The pressure of the gas in the flask (in atm) when Δh = 5.89 cm is 1.04 atm

<h3>Data obtained from the question</h3>

The following data were obtained from the question:

Atmospheric pressure (Pa) = 730.1 torr = 730.1 mmHg
Change in height (Δh) = 5.89 cm
Pressure due to Δh (PΔh) = 5.89 cmHg = 5.89 × 10 = 58.9 mmHg
Pressure of gas (P) =?

<h3>How to determine the pressure of the gas</h3>

The pressure of the gas can be obtained as illustrated below:

P = Pa + PΔh

P = 730.1 + 58.9

P = 789 mmHg

Divide by 760 to express in atm

P = 789 / 760

P = 1.04 atm

Thus, the pressure of the gas when Δh = 5.89 cm is 1.04 atm

Learn more about pressure:

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Missing part of question:

See attached photo

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1 year ago

Flourine is found to undergo 10% radioactivity decay in 366 minutes determine its halflife

yuradex [85]

Answer:

$\boxed{\text{2408 min}}$

Explanation:

The integrated rate law for radioactive decay is

$\ln\dfrac{N_{0}}{N_{t}} = kt$

1. Calculate the decay constant

$\begin{array}{rcl}\ln \dfrac{100}{90} & = & k \times 366\\\\1.054 & = & 366k\\\\k & = & \dfrac{1.054 }{366}\\\\k & = & 2.879 \times 10^{-4} \text{ min}^{-1}\\\end{array}\\\\$

2. Calculate the half-life

$t_{\frac{1}{2}} = \dfrac{\ln2}{k}\\\\t_{\frac{1}{2}} = \dfrac{\ln2}{2.879 \times 10^{-4} \text{ min}^{-1}} = \text{2408 min}\\\\\text{The half-life for decay is } \boxed{\textbf{2408 min}}$

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2 years ago

What volume of a 0.100 M AgNO3 solution is required to completely react with the CaCl2 in 3.00 L of a 0.100 M CaCl2 solution? Th

Andreyy89

Answer:

6.00 LAgNO3

Explanation:

Got it right on Edge. :)

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2 years ago

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