<h3>Answer:</h3>
7.3 × 10⁻⁷ g Ni
<h3>General Formulas and Concepts:</h3><u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Chemistry</u>
<u>Atomic Structure</u>
- Reading a Periodic Table
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<u>Step 1: Define</u>
7.5 × 10¹⁵ atoms Ni
<u>Step 2: Identify Conversions</u>
Avogadro's Number
Molar Mass of Ni - 58.69 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 2 sig figs.</em>
7.30945 × 10⁻⁷ g Ni ≈ 7.3 × 10⁻⁷ g Ni