it hasn't been specified which ticket the question's is asking but I'm guessing the price of the adult ones so $30.00
altogether that's two adults and 3 children who all paid a total of $105.00
let's simplify that to algebra
children tickets = c adults tickets = a
3c + 2a = $105.00
we know that 1c is 0.5a because each child ticket is half of an adults one <em>as stated in the question</em>
so in terms of (adults) a: half of 3 meaning 3×0.5= $1.5 meaning 1.5a
so now <em>3c = 1.5a</em>
so we can substitute and have like terms
meaning 1.5a + 2a= $105
3.5a =$105.00
divide by 3.5 on both sides to get a by itself thus the value of a:
a = $30
so each adult tickets cost $30
X+y+z=t
simple..
there are no other numbers that we have to follow like (1/2x or 3/4y) so it is just all together=t. the x, y, z will equal t because t is the total number of students taking three languages. And that number should be equivalent to x,y,z combined.
otherwise?? i d k<span />
Answer: true
Step-by-step explanation:
It doesn't give any answers? I think the first one is 14 the second one is -4 and the third one is 10
